Что такое ошибка json

Синтаксическая ошибка:JSON.parse:плохой парсинг

Исключения JavaScript, создаваемые JSON.parse() возникают, когда строку не удалось проанализировать как JSON.

SyntaxError: JSON.parse: unterminated string literal
SyntaxError: JSON.parse: bad control character in string literal
SyntaxError: JSON.parse: bad character in string literal
SyntaxError: JSON.parse: bad Unicode escape
SyntaxError: JSON.parse: bad escape character
SyntaxError: JSON.parse: unterminated string
SyntaxError: JSON.parse: no number after minus sign
SyntaxError: JSON.parse: unexpected non-digit
SyntaxError: JSON.parse: missing digits after decimal point
SyntaxError: JSON.parse: unterminated fractional number
SyntaxError: JSON.parse: missing digits after exponent indicator
SyntaxError: JSON.parse: missing digits after exponent sign
SyntaxError: JSON.parse: exponent part is missing a number
SyntaxError: JSON.parse: unexpected end of data
SyntaxError: JSON.parse: unexpected keyword
SyntaxError: JSON.parse: unexpected character
SyntaxError: JSON.parse: end of data while reading object contents
SyntaxError: JSON.parse: expected property name or 
SyntaxError: JSON.parse: end of data when 
SyntaxError: JSON.parse: expected 
SyntaxError: JSON.parse: end of data when property name was expected
SyntaxError: JSON.parse: expected double-quoted property name
SyntaxError: JSON.parse: end of data after property name when 
SyntaxError: JSON.parse: expected 
SyntaxError: JSON.parse: end of data after property value in object
SyntaxError: JSON.parse: expected 
SyntaxError: JSON.parse: expected 
SyntaxError: JSON.parse: property names must be double-quoted strings
SyntaxError: JSON.parse: expected property name or 
SyntaxError: JSON.parse: unexpected character
SyntaxError: JSON.parse: unexpected non-whitespace character after JSON data

JSON.parse('[1, 2, 3, 4,]');
JSON.parse('{"foo": 1,}');

JSON.parse('[1, 2, 3, 4]');
JSON.parse('{"foo": 1}');

JSON.parse("{'foo': 1}");

JSON.parse('{"foo": 1}');

JSON.parse('{"foo": 01}');



JSON.parse('{"foo": 1.}');

JSON.parse('{"foo": 1}');
JSON.parse('{"foo": 1.0}');

JavaScript

• TypeError: недопустимый операнд «экземпляр» «х»

  Исключение JavaScript «недопустимый операнд экземпляра» возникает, когда оператор правых операндов не используется с объектом конструктора, т.е.

• TypeError: ‘x’ не повторяется

  Исключение JavaScript «не является итерируемым» возникает, когда значение, заданное правой частью for…of, функции аргумента, такой как Promise.all TypedArray.from,

• Синтаксическая ошибка:Некорректный формальный параметр

  Исключение JavaScript «искаженный формальный параметр» возникает, когда список аргументов вызова конструктора Function() каким-то образом недействителен.

• URIError:некорректная последовательность URI

  Исключение JavaScript «неверная последовательность URI» возникает, когда декодирование кодирования не было успешным.

Traveling deftly through to the next item in our JavaScript Error Handling series, today we’re taking a hard look at the JSON Parse error. The JSON Parse error, as the name implies, surfaces when using the JSON.parse() method that fails to pass valid JSON as an argument.

In this article, we’ll dig deeper into where JSON Parse errors sit in the JavaScript error hierarchy, as well as when it might appear and how to handle it when it does. Let’s get started!

The Technical Rundown

• All JavaScript error objects are descendants of the Error object, or an inherited object therein.
• The SyntaxError object is inherited from the Error object.
• The JSON Parse error is a specific type of SyntaxError object.

When Should You Use It?

While most developers are probably intimately familiar with JSON and the proper formatting syntax it requires, it doesn’t hurt to briefly review it ourselves, to better understand some common causes of the JSON Parse error in JavaScript.

JavaScript Object Notation, better known as JSON, is a human-readable text format, commonly used to transfer data across the web. The basic structure of JSON consists of objects, which are sets of string: value pairs surrounded by curly braces:

{

    "first": "Jane",

    "last": "Doe"

}

An array is a set of values, surrounded by brackets:

[

    "Jane",

    "Doe"

]

A value can be a string, number, object, array, boolean, or null.

That’s really all there is to the JSON syntax. Since values can be other objects or arrays, JSON can be infinitely nested (theoretically).

In JavaScript, when passing JSON to the JSON.parse() method, the method expects properly formatted JSON as the first argument. When it detects invalid JSON, it throws a JSON Parse error.

For example, one of the most common typos or syntax errors in JSON is adding an extra comma separator at the end of an array or object value set. Notice in the first few examples above, we only use a comma to literally separate values from one another. Here we’ll try adding an extra, or «hanging», comma after our final value:

var printError = function(error, explicit) {

    console.log(`[${explicit ? 'EXPLICIT' : 'INEXPLICIT'}] ${error.name}: ${error.message}`);

}

try {
var json = `
{
«first»: «Jane»,
«last»: «Doe»,
}
`
console.log(JSON.parse(json));
} catch (e) {
if (e instanceof SyntaxError) {
printError(e, true);
} else {
printError(e, false);
}
}

Note: We’re using the backtick (`) string syntax to initialize our JSON, which just allows us to present it in a more readable form. Functionally, this is identical to a string that is contained on a single line.

As expected, our extraneous comma at the end throws a JSON Parse error:

[EXPLICIT] SyntaxError: Unexpected token } in JSON at position 107

In this case, it’s telling us the } token is unexpected, because the comma at the end informs JSON that there should be a third value to follow.

Another common syntax issue is neglecting to surround string values within string: value pairs with quotations ("). Many other language syntaxes use similar key: value pairings to indicate named arguments and the like, so developers may find it easy to forget that JSON requires the string to be explicitly indicated using quotation marks:

var printError = function(error, explicit) {

    console.log(`[${explicit ? 'EXPLICIT' : 'INEXPLICIT'}] ${error.name}: ${error.message}`);

}

try {
var json = `
{
«first»: «Jane»,
last: «Doe»,
}
`
console.log(JSON.parse(json));
} catch (e) {
if (e instanceof SyntaxError) {
printError(e, true);
} else {
printError(e, false);
}
}

Here we forgot quotations around the "last" key string, so we get another JSON Parse error:

[EXPLICIT] SyntaxError: Unexpected token l in JSON at position 76

A few examples are probably sufficient to see how the JSON Parse error comes about, but as it so happens, there are dozens of possible versions of this error, depending on how JSON was improperly formatted. Here’s the full list:

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JSON ( JavaScript Object Notation), is widely used format for asynchronous communication between webpage or mobile application to back-end servers. Due to increasing trend in Single Page Application or Mobile Application, popularity of the JSON is extreme.

Why do we get JSON parse error?

Parsing JSON is a very common task in JavaScript. JSON.parse() is a built-in method in JavaScript which is used to parse a JSON string and convert it into a JavaScript object. If the JSON string is invalid, it will throw a SyntaxError.

const json = '{"result":true, "count":42}';
const obj = JSON.parse(json);
console.log(obj.count);
// expected output: 42
console.log(obj.result);
// expected output: true

How to handle JSON parse error?

There are many ways to handle JSON parse error. In this post, I will show you how to handle JSON parse error in JavaScript.

1. Using try-catch block

The most common way to handle JSON parse error is using try-catch block. If the JSON string is valid, it will return a JavaScript object. If the JSON string is invalid, it will throw a SyntaxError.

try {
  const json = '{"result":true, "count":42}';
  const obj = JSON.parse(json);
  console.log(obj.count);
  // expected output: 42
  console.log(obj.result);
  // expected output: true
} catch (e) {
  console.log(e);
  // expected output: SyntaxError: Unexpected token o in JSON at position 1
}

2. Using if-else block

Another way to handle JSON parse error is using if-else block.

const json = '{"result":true, "count":42}';
const obj = JSON.parse(json);
if (obj instanceof SyntaxError) {
  console.log(obj);
  // expected output: SyntaxError: Unexpected token o in JSON at position 1
} else {
  console.log(obj.count);
  // expected output: 42
  console.log(obj.result);
  // expected output: true
}

3. Using try-catch block with JSON.parse()

The third way to handle JSON parse error is using try-catch block with JSON.parse().

const json = '{"result":true, "count":42}';
const obj = JSON.parse(json, (key, value) => {
  try {
    return JSON.parse(value);
  } catch (e) {
    return value;
  }
});
console.log(obj.count);
// expected output: 42
console.log(obj.result);
// expected output: true

4. Using try-catch block with JSON.parse() and JSON.stringify()

The fourth way to handle JSON parse error is using try-catch block with JSON.parse() and JSON.stringify(). If the JSON string is valid, it will return a JavaScript object. If the JSON string is invalid, it will return a SyntaxError.

const json = '{"result":true, "count":42}';
const obj = JSON.parse(json, (key, value) => {
  try {
    return JSON.parse(value);
  } catch (e) {
    return value;
  }
});
const str = JSON.stringify(obj);
console.log(str);
// expected output: {"result":true,"count":42}