Create sequence ошибка

The reason you’re getting this error is that you’re trying to perform DDL, in this case creating a sequence, within PL/SQL. It is possible to do this, but you must use execute immediate.

As Alex says, you also wouldn’t be able to do this in the declare section. It would look something like this:

begin

   execute immediate 'CREATE SEQUENCE mySequence
                          START WITH 0
                          INCREMENT BY 1';    
end;

However, as Padmarag also says, it’s highly unlikely that you want to do this within PL/SQL. It would be more normal to create a sequence outside and then reference this later. More generally speaking, performing DDL inside a PL/SQL block is a bad idea; there should be no need for you to do it.

You don’t mention what version of Oracle you’re using. From 11g the ways in which you could access sequences got extended. If you’re using 11g then you can access the sequence by creating a variable and assigning the next value in the sequence, .nextval, to this variable:

declare    
   l_seq number;    
begin

   loop
      -- For each loop l_seq will be incremented.
      l_seq := mysequence.nextval;
   -- snip    
end;

If you’re before 11g you must (outside of DML) use a select statement in order to get the next value:

declare
   l_seq number;
begin

   loop
      -- For each loop l_seq will be incremented.
      select mysequence.nextval into l_seq from dual;
   -- snip    
end;

Please bear in mind that a sequence is meant to be a persistent object in the database. There is no need to drop and re-create it each time you want to use it. If you were to run your script, then re-run it the sequence would happily keep increasing the returned value.

Further Reading

  • About sequences
  • Using sequences

trying to add auto_increment to an existing column

ALTER TABLE table_name ALTER COLUMN id_column SET DEFAULT nextval('table_id_column_seq');

try 1:

CREATE SEQUENCE table_id_column_seq AS integer START 1 OWNED BY table.id_column;

Error:

ERROR: sequence must have same owner as table it is linked to

try 2:

CREATE SEQUENCE table_id_column_seq AS integer START 1 OWNED TO postgres;

Error:

ERROR:  syntax error at or near "integer"
LINE 1: CREATE SEQUENCE table_id_column_seq integer START 1...
                                                     ^

As it should be?

asked Aug 24, 2022 at 16:10

Richard's user avatar

2

With modern Postgres versions (i.e. >= 10) it’s better to use identity columns (they do use sequences in the background).

To turn an existing column into an identity column you can use:

ALTER TABLE table_name 
   ALTER COLUMN id_column 
   ADD GENERATED ALWAYS AS IDENTITY;

or

ALTER TABLE table_name 
   ALTER COLUMN id_column 
   ADD GENERATED BY DEFAULT AS IDENTITY;

I prefer the generated always as it will through an error if you try to bypass the automatic generation of values.

If the table already contains data, you need to synchronized the underlying sequence with the values in the table:

select setval(pg_get_serial_sequence('the_table', 'id_column'), max(id))
from the_table;

answered Aug 24, 2022 at 17:51

a_horse_with_no_name's user avatar

As mentioned in the documentation, the OWNED BY refers to table and column this sequence belongs to, not the owning user.

I suggest you perform the CREATE SEQUENCE as the user owning the table, or if this should not be possible, to change the owner to yourself, create the sequence, then change the owner of table and sequence back to the original one.

answered Aug 24, 2022 at 16:24

Robert's user avatar

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11.10.2022, 23:35. Показов 400. Ответов 0


Выполняю некоторое задание по вузу, в ERBuilder создаются таблицы, связи между ними задаются, добавляются последовательности(или триггеры), чтоб первичный ключ постоянно назначался сам при добавлении записи, и добавляются функции на удаление, добавление или обновление записей в таблице. При попытке переноса готовой БД из ERBuilder в pgadmin4 (PostgreSQL 13) выдаёт такую ошибку. При этом, таблицы со всеми колонками и ключами создаются в БД, но перенос ломается либо на стадии создания функций вставки, удаления и обновления, либо на стадии создания последовательности. Не понимаю, как устранить ошибку, пробовал по-разному писать данное выражение, пробовал добавлять название в скобки, добавлял начальное значение, от которого стартует отсчёт последовательности( «START 0» ввёл после названия) .Ниже будут некоторые скрипты, которые относятся к проблеме
Скрипт создания таблицы

SQL
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CREATE TABLE "Postavshik" ( 
  "id_postavshik"           INTEGER NOT NULL,
  "nomer_car"               CHAR(40),
  "adres_postavshika"       CHAR(40),
CONSTRAINT "PK_6" PRIMARY KEY ("id_postavshik")
) 
;

Скрипт триггера для таблицы Postavshik

SQL
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/*============================================================================*/
/*                                  TRIGGERS                                  */
/*============================================================================*/
CREATE SEQUENCE id_postavshik_gen;
CREATE OR REPLACE FUNCTION Postavshik_GEN_ID()
RETURNS TRIGGER AS
$Postavshik_GEN_ID$                      
BEGIN
    NEW.id_postavshik =
        NEXTVAL(‘id_postavshik_gen’::regclass);
    RETURN NEW;
END;
$Postavshik_GEN_ID$
LANGUAGE plpgsql;
CREATE TRIGGER Postavshik_TRIG_ID
BEFORE INSERT ON Postavshik
FOR EACH ROW EXECUTE PROCEDURE Postavshik_GEN_ID();

После первых же строк данного триггера мне выдаёт ошибку, дословно:
«CREATE SEQUENCE id_postavshik_gen
ошибка синтаксиса (примерное положение: ‘CREATE’)»

Добавлено через 16 минут
ШТОШ, проблема в том, что нет «;» после кжадй процедуры, из-за этого CREATE он не понимал

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Hey everyone I need some help with creating tables. I have the script below and it creates a few tables. When i try to run the script it give me this error:

psql:script.sql:10: ERROR:  syntax error at or near "Group"
LINE 6: CREATE TABLE Group(

Can anyone tell me what is going on?

CREATE TABLE Group(
    name        varchar(40) PRIMARY KEY    NOT NULL
);

CREATE TABLE Artist(
    name        varchar(30) PRIMARY KEY    NOT NULL,
        birthplace  varchar(20)                NOT NULL,
        age     int                        NOT NULL   CHECK (age > 0),
        style       varchar(20)                NOT NULL
);

CREATE TABLE Artwork(
    title      varchar(40) PRIMARY KEY     NOT NULL,
        artist     varchar(30)                 NOT NULL   references Artist(name),
        group_name varchar(40)                 NOT NULL   references Group(name),
        year       int                         NOT NULL   CHECK (year > 0),
        type       varchar(30)                 NOT NULL,
        price      money                       NOT NULL,
);

CREATE TABLE Customer(
    cust_id      int PRIMARY KEY   NOT NULL,
    name         varchar(40)       NOT NULL,
        address      varcahr(60)       NOT NULL,
        amount       money             NOT NULL    CHECK(amount > 0),
        like_artist  varchar(30)       NOT NULL    references Artist(name),
        like_group   varchar(40)       NOT NULL    references Group(name)
);

Syntax errors are quite common while coding.

But, things go for a toss when it results in website errors.

PostgreSQL error 42601 also occurs due to syntax errors in the database queries.

At Bobcares, we often get requests from PostgreSQL users to fix errors as part of our Server Management Services.

Today, let’s check PostgreSQL error in detail and see how our Support Engineers fix it for the customers.

What causes error 42601 in PostgreSQL?

PostgreSQL is an advanced database engine. It is popular for its extensive features and ability to handle complex database situations.

Applications like Instagram, Facebook, Apple, etc rely on the PostgreSQL database.

But what causes error 42601?

PostgreSQL error codes consist of five characters. The first two characters denote the class of errors. And the remaining three characters indicate a specific condition within that class.

Here, 42 in 42601 represent the class “Syntax Error or Access Rule Violation“.

In short, this error mainly occurs due to the syntax errors in the queries executed. A typical error shows up as:

Here, the syntax error has occurred in position 119 near the value “parents” in the query.

How we fix the error?

Now let’s see how our PostgreSQL engineers resolve this error efficiently.

Recently, one of our customers contacted us with this error. He tried to execute the following code,

CREATE OR REPLACE FUNCTION prc_tst_bulk(sql text)
RETURNS TABLE (name text, rowcount integer) AS
$$
BEGIN
WITH m_ty_person AS (return query execute sql)
select name, count(*) from m_ty_person where name like '%a%' group by name
union
select name, count(*) from m_ty_person where gender = 1 group by name;
END
$$ LANGUAGE plpgsql;

But, this ended up in PostgreSQL error 42601. And he got the following error message,

ERROR: syntax error at or near "return"
LINE 5: WITH m_ty_person AS (return query execute sql)

Our PostgreSQL Engineers checked the issue and found out the syntax error. The statement in Line 5 was a mix of plain and dynamic SQL. In general, the PostgreSQL query should be either fully dynamic or plain. Therefore, we changed the code as,

RETURN QUERY EXECUTE '
WITH m_ty_person AS (' || sql || $x$)
SELECT name, count(*)::int FROM m_ty_person WHERE name LIKE '%a%' GROUP BY name
UNION
SELECT name, count(*)::int FROM m_ty_person WHERE gender = 1 GROUP BY name$x$;

This resolved the error 42601, and the code worked fine.

[Need more assistance to solve PostgreSQL error 42601?- We’ll help you.]

Conclusion

In short, PostgreSQL error 42601 occurs due to the syntax errors in the code. Today, in this write-up, we have discussed how our Support Engineers fixed this error for our customers.

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var google_conversion_label = «owonCMyG5nEQ0aD71QM»;

Пытаюсь создать табличку, вот такую

CREATE TABLE screens_items (
	screenitemid             bigint                                    NOT NULL,
	screenid                 bigint                                    NOT NULL,
	resourcetype             integer         DEFAULT '0'               NOT NULL,
	resourceid               bigint          DEFAULT '0'               NOT NULL,
	width                    integer         DEFAULT '320'             NOT NULL,
	height                   integer         DEFAULT '200'             NOT NULL,
	x                        integer         DEFAULT '0'               NOT NULL,
	y                        integer         DEFAULT '0'               NOT NULL,
	colspan                  integer         DEFAULT '0'               NOT NULL,
	rowspan                  integer         DEFAULT '0'               NOT NULL,
	elements                 integer         DEFAULT '25'              NOT NULL,
	valign                   integer         DEFAULT '0'               NOT NULL,
	halign                   integer         DEFAULT '0'               NOT NULL,
	style                    integer         DEFAULT '0'               NOT NULL,
	url                      varchar(255)    DEFAULT ''                NOT NULL,
	dynamic                  integer         DEFAULT '0'               NOT NULL,
	sort_triggers            integer         DEFAULT '0'               NOT NULL,
	application              varchar(255)    DEFAULT ''                NOT NULL,
	PRIMARY KEY (screenitemid)
);

Получаю
Error: ОШИБКА:  ошибка синтаксиса (примерное положение: "application")

psql --version
psql (PostgreSQL) 9.4.9 

Вроде слово «application» не зарезервировано?

 
alex_1234 ©

 
(2005-10-10 14:46)
[0]

Строка подключения:

  dbIK.ConnectionString:=
  "Provider=MSDASQL.1;Persist Security Info=False;"+
  "Extended Properties="DSN=Ôàéëû dBASE;DBQ="+
  PathIK+";DefaultDir="+PathIK+";DriverId=533;"+
  "MaxBufferSize=2048;PageTimeout=5;"";

где PathIK — содержит путь к папке с таблицами.
При попытке выполнить запрос:
  q2.Close;
  q2.SQL.Clear;
  q2.SQL.Add("CREATE TABLE PLUCASH(");
  q2.SQL.Add("ARTICUL char(30),");
  q2.SQL.Add("NAME char(80),");
  q2.SQL.Add("MESURIMENT char(10),");
  q2.SQL.Add("MESPRESISI NUMERIC(16,6)");
  q2.SQL.Add(")");
  q2.ExecSQL;

ругается следующим макаром:
....Ошибка синтаксиса в инструкции CREATE TABLE....


 
alex_1234 ©

 
(2005-10-10 14:52)
[1]

Забыл написать:
ориентировочно ошибка в q2.SQL.Add(«MESPRESISI NUMERIC(16,6)»);
т.к. без этого поля все прекрасно создается.
А БДЕ — (СКуэЛь експлорер) — все прекрасно работает :-(


 
Reindeer Moss Eater ©

 
(2005-10-10 14:56)
[2]

А БДЕ — (СКуэЛь експлорер) — все прекрасно работает :-(

Работает, потому что в LocalSQL есть такой тип поля.


 
alex_1234 ©

 
(2005-10-10 15:00)
[3]

Но ведь не может быть такого, чтобы в ADO не было аналогичного типа….
Подскажите, в каком хлп-файле нарыть типы полей поддерживаемых АДО…


 
sniknik ©

 
(2005-10-10 15:38)
[4]

> CREATE TABLE PLUCASH … ARTICUL …
;о) супермаг dos. ;о)

просто
MESPRESISI NUMERIC
и все без всяких (16,6). поддерживается только емулируемый тип (под double) с размерностью 20,5 который и будет создан по умолчанию. без указаний.

но это тебе конечно не поможет. -> супермаг… %о)

> в каком хлп-файле нарыть типы полей поддерживаемых АДО…
Jet — JETSQL40.CHM. а АДО поддерживает все что поддерживает подключаемый драйвер/провайдер. кроме разных мелких :) досадных недоразумений. (бигинт…)


 
mr.il ©

 
(2005-10-10 15:47)
[5]

Попробуй прописать название таблицы с расширением — PLUCASH.dbf.


 
alex_1234 ©

 
(2005-10-10 16:04)
[6]

mr.il : писал — не выходит каменный цветок.
Попробую как писал sniknik — а вдруг «съест»


 
Reindeer Moss Eater ©

 
(2005-10-10 16:56)
[7]

Но ведь не может быть такого, чтобы в ADO не было аналогичного типа….

Почему не может? Может. Зависит от завихрений автора используемого провайдера. Кроме того, этот типа там может просто называться по другому.


 
Reindeer Moss Eater ©

 
(2005-10-10 16:58)
[8]

Судя по всему у тебя провайдер использует ODBC.
Вот и посмотри как по стандарту ODBC зовется такое поле.


 
Anatoly Podgoretsky ©

 
(2005-10-10 18:55)
[9]

Reindeer Moss Eater ©   (10.10.05 16:58) [8]
Не судя по всему, а так и есть MSDASQL


 
alex_1234 ©

 
(2005-10-11 16:23)
[10]

Блин, как бы мне этого не хотелось — а пришлось делать через «ж..у»:

  dbMag.ConnectionString:=
  "Provider=MSDASQL.1;Persist Security Info=False;"+
  "Extended Properties="DSN=Òàáëèöû Visual FoxPro;UID=;"+
  "SourceDB="+PathMag+";SourceType=DBF;Exclusive=No;"+
  "BackgroundFetch=Yes;Collate=Machine;Null=Yes;"+
  "Deleted=Yes;"";
  dbIK.ConnectionString:=
  "Provider=Microsoft.Jet.OLEDB.4.0;Data Source="+PathIK+
  ";Extended Properties=dBase IV;Persist Security Info=False";

т.е. для разных запросов — разные типы полключения:
для таблиц FoxPro — MSDASQL,
а для dBase — Microsoft.Jet.OLEDB

Утешает, что в предыдущих версиях был еще БДЕ, а тут его не будет…


 
sniknik ©

 
(2005-10-11 17:39)
[11]

> был еще БДЕ, а тут его не будет…
будет!!! ;о)) оно живее всех живых. Jet использует BDE.  полное если стоит, либо урезаное(лайт версия унутрях) если нет.


 
alex_1234 ©

 
(2005-10-11 17:53)
[12]

Да я бы все на БДЕ делал-бы (да и в комплект 4 СуперМага она входит), но она не хочет делать один запрос (4 таблички вяжутся, правда весьма несложно) — ругается на индексный файл (таблица Фокса)….


If you’re getting an error that reads something like “MINVALUE (1) must be less than MAXVALUE (1)” in PostgreSQL when you’re trying to create a sequence, it’s probably because your sequence’s minimum possible value is higher than the maximum value.

To fix this issue, be sure that the sequence’s maximum value is greater than the minimum value.

Example of Error

Here’s an example of code that produces the error:

CREATE SEQUENCE Sequence1
    MINVALUE 1
    MAXVALUE 1;

Result:

ERROR:  MINVALUE (1) must be less than MAXVALUE (1)

We can get the same error even when we don’t explicitly specify a MAXVALUE.

Example:

CREATE SEQUENCE Sequence1
    INCREMENT -1
    MINVALUE 1;

Result:

ERROR:  MINVALUE (1) must be less than MAXVALUE (-1)

In this case I tried to create a descending sequence. I specified a MINVALUE but not a MAXVALUE. In this case I specified a MINVALUE that’s lower than what the default MAXVALUE would be set to, and so I received the error.

The error message tells us that the MAXVALUE is set to -1. In this case it’s because I didn’t specify a MAXVALUE value, and therefore it used the default value of -1. This is also what the START value would default to.

Solution

One way to deal with this issue is to increase the MAXVALUE, decrease the MINVALUE value, or do both.

Here’s an example of fixing the first example by increasing the MAXVALUE:

CREATE SEQUENCE Sequence1
    MINVALUE 1
    MAXVALUE 10000000000;

Result:

Commands completed successfully

In this case I increased the MAXVALUE to a much greater amount. The code ran without error, and my client told me that the command completed successfully.

Alternatively, we could have reduced the MINVALUE value. Or we could have done both – increased the MAXVALUE while decreasing the MINVALUE value.

The Descending Sequence

Regarding our second example, we tried to create a descending sequence and we didn’t specify a MAXVALUE value. This caused the MAXVALUE value to be set to the default value of -1. For descending sequences, the default START value is the MAXVALUE value.

In other words, if we don’t specify a START value, then it will start at the MAXVALUE amount. And if we don’t specify a MAXVALUE, then it is automatically set at -1 for descending sequences.

So, we can fix the second example by specifying a MAXVALUE value and ensuring that it’s greater than the MINVALUE:

CREATE SEQUENCE Sequence1
    INCREMENT -1
    MINVALUE 1
    MAXVALUE 10000000000;

Result:

Commands completed successfully

This time the command ran successfully.

The ORA-02289 error is a common issue faced by Oracle Database users. This error message indicates that the sequence you are trying to reference does not exist in the database. In this guide, we will walk you through various troubleshooting tips to resolve the ORA-02289 error and answer some frequently asked questions.

Table of Contents

  • Understanding ORA-02289 Error
  • Common Causes of ORA-02289 Error
  • How to Fix ORA-02289 Error
  • Check Sequence Name
  • Grant Required Privileges
  • Create the Missing Sequence
  • FAQs

Understanding ORA-02289 Error

The ORA-02289 error message is displayed as:

ORA-02289: Sequence does not exist

This error occurs when you attempt to reference a sequence that is not present in the database. The most common scenarios are when trying to insert data into a table using a sequence or when trying to fetch the next value from a sequence that does not exist.

Common Causes of ORA-02289 Error

  1. The sequence name is misspelled, or the case is incorrect.
  2. The sequence does not exist in the database.
  3. The user does not have the necessary privileges to access the sequence.

How to Fix ORA-02289 Error

Check Sequence Name

First, verify the sequence name referenced in your SQL statement. Ensure that it is spelled correctly and that the case (upper or lower) matches the actual sequence name in the database. You can check the list of sequences in your database using the following query:

SELECT sequence_name FROM user_sequences;

Grant Required Privileges

If the sequence exists and the name is correct, ensure that the user running the SQL statement has the necessary privileges to access the sequence. The user should have SELECT privileges on the sequence. The following SQL statement grants the required privileges:

GRANT SELECT ON schema_name.sequence_name TO user_name;

Replace schema_name, sequence_name, and user_name with the appropriate values.

Create the Missing Sequence

If the sequence does not exist in the database, you will need to create it. Use the CREATE SEQUENCE statement to create a new sequence:

CREATE SEQUENCE schema_name.sequence_name
START WITH 1
INCREMENT BY 1
CACHE 20;

Replace schema_name and sequence_name with the desired values.

FAQs

What is a sequence in Oracle Database?

A sequence is a database object that generates a unique and sequential set of numbers. It is commonly used to generate primary key values when inserting data into tables. Learn more about sequences in Oracle Database.

How do I view all sequences in Oracle Database?

To view all sequences in the database, execute the following query:

SELECT sequence_name FROM all_sequences;

How do I get the current value of a sequence in Oracle Database?

To get the current value of a sequence, execute the following query:

SELECT sequence_name.CURRVAL FROM DUAL;

Replace sequence_name with the actual name of the sequence.

How do I reset a sequence in Oracle Database?

To reset a sequence, you can use the ALTER SEQUENCE statement with the RESTART WITH clause:

ALTER SEQUENCE schema_name.sequence_name RESTART WITH 1;

Replace schema_name and sequence_name with the appropriate values.

Can I create a sequence with a specific increment value in Oracle Database?

Yes, you can create a sequence with a specific increment value using the INCREMENT BY clause in the CREATE SEQUENCE statement:

CREATE SEQUENCE schema_name.sequence_name
START WITH 1
INCREMENT BY custom_increment_value
CACHE 20;

Replace schema_name, sequence_name, and custom_increment_value with the desired values.

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