Float object is not iterable python ошибка

Floats and iterables are distinct objects In Python. A float is any decimal point number, and an iterable is an object capable of returning elements one at a time, for example, a list. A float is a single value and does not contain other values. If you try to iterate over a float, you will raise the error “TypeError: ‘float’ object is not iterable“.

To solve this error, ensure you use the range() method, for example,

for number in range(floating_point_number)

to iterate over a range of numbers up to the specified floating_point_number.

This tutorial will go through the error in detail. We will go through two example scenarios and learn how to solve them.

TypeError: ‘float’ object not iterable

What is a TypeError?

A TypeError occurs when we try to perform an operation on the wrong type of object. For example, if we try to calculate the square root of a list instead of an integer or a floating-point number, then a TypeError will be generated by the Python interpreter.

Difference Between a Float and an Iterable

Iterables are containers that can store multiple values and return them one by one. Iterables can store any number of values, and the values can either be the same type or different types. You can go to the next item in an iterable object using the next() method.

A floating-point number is any number with a decimal point. You can define a floating-point number in Python by defining a variable and assigning a decimal point number to it.

x = 4.2

print(type(x))

class 'float'

Floating-point numbers do not store multiple values like a list or a dictionary. If you try to iterate over a float, you will raise the error “TypeError: ‘float’ object is not iterable” because float does not support iteration.

You will get a similar error if you try to iterate over an integer or a NoneType object.

Example #1: Iterate Over a Floating Point Number

Let’s look at an example where we initialize a floating-point number and iterate over it.

# Define floating point number

float_num = 10.0 

# Iterate over the floating point number

for num in float_num:

    print(num)

Let’s see what happens when we run the code:

TypeError                                 Traceback (most recent call last)
      1 for num in float_num:
      2     print(num)
      3 

TypeError: 'float' object is not iterable

We raise the error because Python does not support iteration on a floating-point number.

Solution #1: Convert float to string Using the str() Method

The first solution involves converting the float_num object to a string using the str() method and iterating over every digit. We can do iteration over a string because the string type is iterable. However, the for loop will return each character of the float_num string.

# Define floating point number

float_num = 10.0 

# Iterate over the floating point number

for digit in str(float_num):

    print(digit)

Solution #2: Iterate Using the range() Method

To print the range of numbers, we can use the int() method to convert the number to an integer and then use the integer as input to the range() method. The range() method only accepts integer numbers, in which case we have to convert any floating-point number that we want to iterate over to an integer. The range() method returns an iterable object which we can iterate over using a for loop.

# Define floating point number

float_num = 30.0 

# Convert the float number to an integer

int_num = int(float_num)

# Iterate over the floating point number

for num in range(int_num):

    print(num)

Let’s see what happens when we run the revised code:

0
1
2
3
4
5
6
7
8
9

Example #2: Determine if a Number is Prime

Let’s look at another example where we write a program to check if a number entered by the user is prime or not. Prime numbers are only divisible by themselves, and 1. To start, we will ask the user to insert the number to determine whether it is prime or not.

number = float(input("Enter a number:  "))

Then we define a function that determines whether the number is prime by using the modulo operator %. If the remained of x % y equals zero, then y is a factor of x. Prime numbers have two factors, one and itself.

# Function to determine if number is prime or not

def prime_number_calc(num):

    for i in num:
        # Ensure we do not divide the number by zero or one

        if i > 1:

            if num % i == 0:

                 print(f'{num} is not prime')

                 break

    # If the loop runs completely the number is prime

    else:

        print(f'{num} is a prime number')

prime_number_calc(number)

Let’s run the code to see what happens:

TypeError                                 Traceback (most recent call last)
      1 def prime_number_calc(num):
      2     for i in num:
      3         if i > 1:
      4             if num % i == 0:
      5                 print(f'{num} is not prime')

TypeError: 'float' object is not iterable

The Python interpreter throws the TypeError because a floating-point number is not a suitable type to iterate over. A for loop requires an iterable object to loop over.

Solution

To solve this problem, we need to convert the input number to an integer using int() and pass the integer the range() method instead of the float. Let’s look at the revised code:

def prime_number_calc(num):

     for i in range(int(num)):

         if i > 1:

             if num % i == 0:

                 print(f'{num} is not prime')

                 break
     else:

         print(f'{num} is a prime number')

number = float(input("Enter a number:  "))

prime_number_calc(number)

Let’s run the code to see what happens:

Enter a number:  17.0

17.0 is a prime number

Our code successfully prints the result that 17.0 is a prime number.

Summary

Congratulations on reading to the end of this tutorial. The error “TypeError: ‘float’ object is not iterable” occurs when you try to iterate over a floating-point number as if it were an iterable object like a list.

You must use the range() method to iterate over a collection of numbers. However, you must convert the float to an integer beforehand passing it to the range() method. If you want to iterate over the digits of the float, you can convert the float to a string and use the range() function.

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Python can only iterate over an iterable object. This is a type of object that can return its members one at a time. If you try to iterate over a non-iterable object, like a floating-point number, you see an error that says “TypeError: ‘float’ object not iterable”.

In this guide, we talk about what this error means and why you may encounter it. We walk through an example to help you understand how to resolve this error in your code.

TypeError: ‘float’ object not iterable

Iterable objects include list, strings, tuples, and dictionaries. When you run a for loop on these data types, each value in the object is returned one by one.

Numbers, such as integers and floating points, are not iterable. There are no members in an integer or a floating-point that can be returned in a loop.

The result of the “TypeError: ‘float’ object not iterable” error is usually trying to use a number to tell a for loop how many times to execute instead of using a range() statement.

An Example Scenario

Here, we write a program that calculates the factors of a number. To start, we ask the user to insert a number whose factors they want to calculate:

factor = float(input("Enter a number: "))

The input() method returns a string. We cannot perform mathematical operations on a string. We’ve used the float() method to convert the value returned by input() to a floating-point number so that we can use it in a math operation.

Next, we write a for loop that calculates the factors of our number:

for n in factor:
	if factor % n == 0:
		print("{} is a factor of {}.".format(factor, n))

This loop should go through every number until it reaches “factor”.

This loop uses the modulo operator to check whether there is a remainder left after dividing the factor by “n”, which is the number in an iteration of our loop. If there is a remainder, “n” is not a factor. If there is a remainder, our “if” statement executes and prints a message to the console.

Run our code and see what happens:

Enter a number: 8
Traceback (most recent call last):
  File "main.py", line 3, in <module>
	for n in factor:
TypeError: 'float' object is not iterable

Our code returns a TypeError.

The Solution

In our example above, we’ve tried to iterate over “factor”, which is a float. We cannot iterate over a floating-point number in a for loop. Instead, we should iterate over a range of numbers between 1 and the number whose factor we want to calculate.

To fix our code, we need to use a range() statement. The range() statement generates a list of numbers in a specified range upon which a for loop can iterate. Let’s revise our for loop to use a range() statement:

for n in range(1, int(factor) + 1):
	if factor % n == 0:
		print("{} is a factor of {}.".format(factor, n))

Our range() statement generates a list of numbers between one and the value of “factor” plus one.

We have added 1 to the upper end of our range so that our “factor” number is considered a factor. Our for loop can then iterate over this list. We’ve converted “factor” to an integer in our code because the range() statement does not accept floating point numbers.

Run our code again and see what happens:

8.0 is a factor of 1.
8.0 is a factor of 2.
8.0 is a factor of 4.
8.0 is a factor of 8.

Our code successfully returns a list of all the factors of the number we inserted into our program.

Conclusion

The Python “TypeError: ‘float’ object not iterable” error is caused when you try to iterate over a floating point number as if it were an iterable object, like a list or a dictionary.

To solve this error, use a range() statement if you want to iterate over a number. A range statement generates a list of numbers in a given range upon which a for loop can iterate.

Now you’re ready to fix this common Python error in your code!

Float is an non iterable python datatype and typeerror float object is not iterable occurs only when any python statement invokes float as iterable element in loop etc. In this article, we will explore multiple scenarios where we face this error. We will understand the root cause of this error and apply the same to fix different scenarios.

Typeerror float object is not iterable ( Deep Dive in Root Cause ) –

Usually we run the loop over iterable objects. In each iteration , It returns next value for the sequence. Like list, dict, tuple are iterable object. But float is not iterable object. Its single value element. Lets see with code for more clarity-

element= 7.5
for i in element:
  print(i)

How to check float is iterable or not ?

If any python object is iterable then its override the method __iter__() in its class and the best way to check the same is using dir() function.

print(dir(float))

Output –

['__abs__', '__add__', '__bool__', '__class__', '__delattr__', '__dir__', '__divmod__', '__doc__', '__eq__', '__float__', '__floordiv__', '__format__', '__ge__', '__getattribute__', '__getformat__', '__getnewargs__', '__gt__', '__hash__', '__init__', '__init_subclass__', '__int__', '__le__', '__lt__', '__mod__', '__mul__', '__ne__', '__neg__', '__new__', '__pos__', '__pow__', '__radd__', '__rdivmod__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rmod__', '__rmul__', '__round__', '__rpow__', '__rsub__', '__rtruediv__', '__set_format__', '__setattr__', '__sizeof__', '__str__', '__sub__', '__subclasshook__', '__truediv__', '__trunc__', 'as_integer_ratio', 'conjugate', 'fromhex', 'hex', 'imag', 'is_integer', 'real']

Since __iter__() is missing hence float is not iterable object

There are infinite business logic where we face this error. But developer intention and root cause for this error is common everywhere. In this section lets understand the same.

Case 1 : Solution for looping scenario using range –

Usually when we want to loop any logic, we need to define the counter and there if we pass float we get this error. The straight fix for this using range. Basically range converts number to an iterable list. But make sure range only accepts interger values so if we pass float directly into range function we get this error – Typeerror: float object cannot be interpreted as an integer . Hence we will convert the float to int and then pass in range() function. Here is the implementation-

element= 7.5
for i in range(int(element)):
  print(i)

Case 2 : Float iteration as str object –

As you know str objects in python are iterable. In some scenarios developer needs to iterate Float object as string only. But they somehow forgot to typecast the float object into str . Hence they get this error.

element= 7.5
for i in str(element):
  print(i)

Here interpreter is iterating over the digits of float object as string.

Similar Typeerror on Iterable objects –

Just like Float, int and NoneType objects are not iterables. These error are similar to each others but occurs in different business logics. You can read more about them here-

Typeerror nonetype object is not iterable : Complete Solution

Typeerror int object is not iterable : Root cause and Fix

Thanks 

Data Science Learner Team