Ошибка 42601 postgresql

Syntax errors are quite common while coding.

But, things go for a toss when it results in website errors.

PostgreSQL error 42601 also occurs due to syntax errors in the database queries.

At Bobcares, we often get requests from PostgreSQL users to fix errors as part of our Server Management Services.

Today, let’s check PostgreSQL error in detail and see how our Support Engineers fix it for the customers.

What causes error 42601 in PostgreSQL?

PostgreSQL is an advanced database engine. It is popular for its extensive features and ability to handle complex database situations.

Applications like Instagram, Facebook, Apple, etc rely on the PostgreSQL database.

But what causes error 42601?

PostgreSQL error codes consist of five characters. The first two characters denote the class of errors. And the remaining three characters indicate a specific condition within that class.

Here, 42 in 42601 represent the class “Syntax Error or Access Rule Violation“.

In short, this error mainly occurs due to the syntax errors in the queries executed. A typical error shows up as:

Here, the syntax error has occurred in position 119 near the value “parents” in the query.

How we fix the error?

Now let’s see how our PostgreSQL engineers resolve this error efficiently.

Recently, one of our customers contacted us with this error. He tried to execute the following code,

CREATE OR REPLACE FUNCTION prc_tst_bulk(sql text)
RETURNS TABLE (name text, rowcount integer) AS
$$
BEGIN
WITH m_ty_person AS (return query execute sql)
select name, count(*) from m_ty_person where name like '%a%' group by name
union
select name, count(*) from m_ty_person where gender = 1 group by name;
END
$$ LANGUAGE plpgsql;

But, this ended up in PostgreSQL error 42601. And he got the following error message,

ERROR: syntax error at or near "return"
LINE 5: WITH m_ty_person AS (return query execute sql)

Our PostgreSQL Engineers checked the issue and found out the syntax error. The statement in Line 5 was a mix of plain and dynamic SQL. In general, the PostgreSQL query should be either fully dynamic or plain. Therefore, we changed the code as,

RETURN QUERY EXECUTE '
WITH m_ty_person AS (' || sql || $x$)
SELECT name, count(*)::int FROM m_ty_person WHERE name LIKE '%a%' GROUP BY name
UNION
SELECT name, count(*)::int FROM m_ty_person WHERE gender = 1 GROUP BY name$x$;

This resolved the error 42601, and the code worked fine.

[Need more assistance to solve PostgreSQL error 42601?- We’ll help you.]

Conclusion

In short, PostgreSQL error 42601 occurs due to the syntax errors in the code. Today, in this write-up, we have discussed how our Support Engineers fixed this error for our customers.

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Return selected columns

CREATE OR REPLACE FUNCTION get_user_by_username(_username text
                                              , _online bool DEFAULT false)
  RETURNS TABLE (
    user_id int
  , user_name varchar
  , last_activity timestamptz
  )
  LANGUAGE plpgsql AS
$func$
BEGIN
   IF _online THEN
      RETURN QUERY
      UPDATE users u 
      SET    last_activity = current_timestamp  -- ts with time zone
      WHERE  u.user_name = _username
      RETURNING u.user_id
              , u.user_name
              , u.last_activity;
   ELSE
      RETURN QUERY
      SELECT u.user_id
           , u.user_name
           , u.last_activity
      FROM   users u
      WHERE  u.user_name = _username;
   END IF;
END
$func$;

Call:

SELECT * FROM get_user_by_username('myuser', true);

You had DECLARE result record; but didn’t use the variable. I deleted the cruft.

You can return the record directly from the UPDATE, which is much faster than calling an additional SELECT statement. Use RETURN QUERY and UPDATE with a RETURNING clause.

If the user is not _online, default to a plain SELECT. This is also the (safe) default if the second parameter is omitted — which is only possible after providing that default with DEFAULT false in the function definition.

If you don’t table-qualify column names (tablename.columnname) in queries inside the function, be wary of naming conflicts between column names and named parameters, which are visible (most) everywhere inside a function.
You can also avoid such conflicts by using positional references ($n) for parameters. Or use a prefix that you never use for column names: like an underscore (_username).

If users.username is defined unique in your table, then LIMIT 1 in the second query is just cruft. If it is not, then the UPDATE can update multiple rows, which is most likely wrong. I assume a unique username and trim the noise.

Define the return type of the function (like @ertx demonstrated) or you have to provide a column definition list with every function call, which is awkward.

Creating a type for that purpose (like @ertx proposed) is a valid approach, but probably overkill for a single function. That was the way to go in old versions of Postgres before we had RETURNS TABLE for that purpose — like demonstrated above.

You do not need a loop for this simple function.

Every function needs a language declaration. LANGUAGE plpgsql in this case.

I use timestamptz (timestamp with time zone) instead of timestamp (timestamp without time zone), which is the sane default. See:

  • Ignoring time zones altogether in Rails and PostgreSQL

Return (set of) whole row(s)

To return all columns of the existing table users, there is a simpler way. Postgres automatically defines a composite type of the same name for every table. Just use RETURNS SETOF users to vastly simplify the query:

CREATE OR REPLACE FUNCTION get_user_by_username(_username text
                                              , _online bool DEFAULT false)
  RETURNS SETOF users
  LANGUAGE plpgsql AS
$func$
BEGIN
   IF _online THEN
      RETURN QUERY
      UPDATE users u 
      SET    last_activity = current_timestamp
      WHERE  u.user_name = _username
      RETURNING u.*;
   ELSE
      RETURN QUERY
      SELECT *
      FROM   users u
      WHERE  u.user_name = _username;
   END IF;
END
$func$;

Return whole row plus custom addition

To address the question added by TheRealChx101 in a comment below:

What if you also have a calculated value in addition to a whole table? 😑

Not as simple, but doable. We can send the whole row type as one field, and add more:

CREATE OR REPLACE FUNCTION get_user_by_username3(_username text
                                               , _online bool DEFAULT false)
  RETURNS TABLE (
    users_row users
  , custom_addition text
  )
  LANGUAGE plpgsql AS
$func$
BEGIN
   IF _online THEN
      RETURN QUERY
      UPDATE users u 
      SET    last_activity = current_timestamp  -- ts with time zone
      WHERE  u.user_name = _username
      RETURNING u  -- whole row
              , u.user_name || u.user_id;
   ELSE
      RETURN QUERY
      SELECT u, u.user_name || u.user_id
      FROM   users u
      WHERE  u.user_name = _username;
   END IF;
END
$func$;

The «magic» is in the function call, where we (optionally) decompose the row type:

SELECT (users_row).*, custom_addition FROM get_user_by_username('foo', true);

db<>fiddle here (showing all)


If you need something more «dynamic», consider:

  • Refactor a PL/pgSQL function to return the output of various SELECT queries
Error Code Condition Name
Class 00 — Successful Completion
00000 successful_completion
Class 01 — Warning
01000 warning
0100C dynamic_result_sets_returned
01008 implicit_zero_bit_padding
01003 null_value_eliminated_in_set_function
01007 privilege_not_granted
01006 privilege_not_revoked
01004 string_data_right_truncation
01P01 deprecated_feature
Class 02 — No Data (this is also a warning class per the SQL standard)
02000 no_data
02001 no_additional_dynamic_result_sets_returned
Class 03 — SQL Statement Not Yet Complete
03000 sql_statement_not_yet_complete
Class 08 — Connection Exception
08000 connection_exception
08003 connection_does_not_exist
08006 connection_failure
08001 sqlclient_unable_to_establish_sqlconnection
08004 sqlserver_rejected_establishment_of_sqlconnection
08007 transaction_resolution_unknown
08P01 protocol_violation
Class 09 — Triggered Action Exception
09000 triggered_action_exception
Class 0A — Feature Not Supported
0A000 feature_not_supported
Class 0B — Invalid Transaction Initiation
0B000 invalid_transaction_initiation
Class 0F — Locator Exception
0F000 locator_exception
0F001 invalid_locator_specification
Class 0L — Invalid Grantor
0L000 invalid_grantor
0LP01 invalid_grant_operation
Class 0P — Invalid Role Specification
0P000 invalid_role_specification
Class 0Z — Diagnostics Exception
0Z000 diagnostics_exception
0Z002 stacked_diagnostics_accessed_without_active_handler
Class 20 — Case Not Found
20000 case_not_found
Class 21 — Cardinality Violation
21000 cardinality_violation
Class 22 — Data Exception
22000 data_exception
2202E array_subscript_error
22021 character_not_in_repertoire
22008 datetime_field_overflow
22012 division_by_zero
22005 error_in_assignment
2200B escape_character_conflict
22022 indicator_overflow
22015 interval_field_overflow
2201E invalid_argument_for_logarithm
22014 invalid_argument_for_ntile_function
22016 invalid_argument_for_nth_value_function
2201F invalid_argument_for_power_function
2201G invalid_argument_for_width_bucket_function
22018 invalid_character_value_for_cast
22007 invalid_datetime_format
22019 invalid_escape_character
2200D invalid_escape_octet
22025 invalid_escape_sequence
22P06 nonstandard_use_of_escape_character
22010 invalid_indicator_parameter_value
22023 invalid_parameter_value
22013 invalid_preceding_or_following_size
2201B invalid_regular_expression
2201W invalid_row_count_in_limit_clause
2201X invalid_row_count_in_result_offset_clause
2202H invalid_tablesample_argument
2202G invalid_tablesample_repeat
22009 invalid_time_zone_displacement_value
2200C invalid_use_of_escape_character
2200G most_specific_type_mismatch
22004 null_value_not_allowed
22002 null_value_no_indicator_parameter
22003 numeric_value_out_of_range
2200H sequence_generator_limit_exceeded
22026 string_data_length_mismatch
22001 string_data_right_truncation
22011 substring_error
22027 trim_error
22024 unterminated_c_string
2200F zero_length_character_string
22P01 floating_point_exception
22P02 invalid_text_representation
22P03 invalid_binary_representation
22P04 bad_copy_file_format
22P05 untranslatable_character
2200L not_an_xml_document
2200M invalid_xml_document
2200N invalid_xml_content
2200S invalid_xml_comment
2200T invalid_xml_processing_instruction
22030 duplicate_json_object_key_value
22031 invalid_argument_for_sql_json_datetime_function
22032 invalid_json_text
22033 invalid_sql_json_subscript
22034 more_than_one_sql_json_item
22035 no_sql_json_item
22036 non_numeric_sql_json_item
22037 non_unique_keys_in_a_json_object
22038 singleton_sql_json_item_required
22039 sql_json_array_not_found
2203A sql_json_member_not_found
2203B sql_json_number_not_found
2203C sql_json_object_not_found
2203D too_many_json_array_elements
2203E too_many_json_object_members
2203F sql_json_scalar_required
2203G sql_json_item_cannot_be_cast_to_target_type
Class 23 — Integrity Constraint Violation
23000 integrity_constraint_violation
23001 restrict_violation
23502 not_null_violation
23503 foreign_key_violation
23505 unique_violation
23514 check_violation
23P01 exclusion_violation
Class 24 — Invalid Cursor State
24000 invalid_cursor_state
Class 25 — Invalid Transaction State
25000 invalid_transaction_state
25001 active_sql_transaction
25002 branch_transaction_already_active
25008 held_cursor_requires_same_isolation_level
25003 inappropriate_access_mode_for_branch_transaction
25004 inappropriate_isolation_level_for_branch_transaction
25005 no_active_sql_transaction_for_branch_transaction
25006 read_only_sql_transaction
25007 schema_and_data_statement_mixing_not_supported
25P01 no_active_sql_transaction
25P02 in_failed_sql_transaction
25P03 idle_in_transaction_session_timeout
Class 26 — Invalid SQL Statement Name
26000 invalid_sql_statement_name
Class 27 — Triggered Data Change Violation
27000 triggered_data_change_violation
Class 28 — Invalid Authorization Specification
28000 invalid_authorization_specification
28P01 invalid_password
Class 2B — Dependent Privilege Descriptors Still Exist
2B000 dependent_privilege_descriptors_still_exist
2BP01 dependent_objects_still_exist
Class 2D — Invalid Transaction Termination
2D000 invalid_transaction_termination
Class 2F — SQL Routine Exception
2F000 sql_routine_exception
2F005 function_executed_no_return_statement
2F002 modifying_sql_data_not_permitted
2F003 prohibited_sql_statement_attempted
2F004 reading_sql_data_not_permitted
Class 34 — Invalid Cursor Name
34000 invalid_cursor_name
Class 38 — External Routine Exception
38000 external_routine_exception
38001 containing_sql_not_permitted
38002 modifying_sql_data_not_permitted
38003 prohibited_sql_statement_attempted
38004 reading_sql_data_not_permitted
Class 39 — External Routine Invocation Exception
39000 external_routine_invocation_exception
39001 invalid_sqlstate_returned
39004 null_value_not_allowed
39P01 trigger_protocol_violated
39P02 srf_protocol_violated
39P03 event_trigger_protocol_violated
Class 3B — Savepoint Exception
3B000 savepoint_exception
3B001 invalid_savepoint_specification
Class 3D — Invalid Catalog Name
3D000 invalid_catalog_name
Class 3F — Invalid Schema Name
3F000 invalid_schema_name
Class 40 — Transaction Rollback
40000 transaction_rollback
40002 transaction_integrity_constraint_violation
40001 serialization_failure
40003 statement_completion_unknown
40P01 deadlock_detected
Class 42 — Syntax Error or Access Rule Violation
42000 syntax_error_or_access_rule_violation
42601 syntax_error
42501 insufficient_privilege
42846 cannot_coerce
42803 grouping_error
42P20 windowing_error
42P19 invalid_recursion
42830 invalid_foreign_key
42602 invalid_name
42622 name_too_long
42939 reserved_name
42804 datatype_mismatch
42P18 indeterminate_datatype
42P21 collation_mismatch
42P22 indeterminate_collation
42809 wrong_object_type
428C9 generated_always
42703 undefined_column
42883 undefined_function
42P01 undefined_table
42P02 undefined_parameter
42704 undefined_object
42701 duplicate_column
42P03 duplicate_cursor
42P04 duplicate_database
42723 duplicate_function
42P05 duplicate_prepared_statement
42P06 duplicate_schema
42P07 duplicate_table
42712 duplicate_alias
42710 duplicate_object
42702 ambiguous_column
42725 ambiguous_function
42P08 ambiguous_parameter
42P09 ambiguous_alias
42P10 invalid_column_reference
42611 invalid_column_definition
42P11 invalid_cursor_definition
42P12 invalid_database_definition
42P13 invalid_function_definition
42P14 invalid_prepared_statement_definition
42P15 invalid_schema_definition
42P16 invalid_table_definition
42P17 invalid_object_definition
Class 44 — WITH CHECK OPTION Violation
44000 with_check_option_violation
Class 53 — Insufficient Resources
53000 insufficient_resources
53100 disk_full
53200 out_of_memory
53300 too_many_connections
53400 configuration_limit_exceeded
Class 54 — Program Limit Exceeded
54000 program_limit_exceeded
54001 statement_too_complex
54011 too_many_columns
54023 too_many_arguments
Class 55 — Object Not In Prerequisite State
55000 object_not_in_prerequisite_state
55006 object_in_use
55P02 cant_change_runtime_param
55P03 lock_not_available
55P04 unsafe_new_enum_value_usage
Class 57 — Operator Intervention
57000 operator_intervention
57014 query_canceled
57P01 admin_shutdown
57P02 crash_shutdown
57P03 cannot_connect_now
57P04 database_dropped
57P05 idle_session_timeout
Class 58 — System Error (errors external to PostgreSQL itself)
58000 system_error
58030 io_error
58P01 undefined_file
58P02 duplicate_file
Class 72 — Snapshot Failure
72000 snapshot_too_old
Class F0 — Configuration File Error
F0000 config_file_error
F0001 lock_file_exists
Class HV — Foreign Data Wrapper Error (SQL/MED)
HV000 fdw_error
HV005 fdw_column_name_not_found
HV002 fdw_dynamic_parameter_value_needed
HV010 fdw_function_sequence_error
HV021 fdw_inconsistent_descriptor_information
HV024 fdw_invalid_attribute_value
HV007 fdw_invalid_column_name
HV008 fdw_invalid_column_number
HV004 fdw_invalid_data_type
HV006 fdw_invalid_data_type_descriptors
HV091 fdw_invalid_descriptor_field_identifier
HV00B fdw_invalid_handle
HV00C fdw_invalid_option_index
HV00D fdw_invalid_option_name
HV090 fdw_invalid_string_length_or_buffer_length
HV00A fdw_invalid_string_format
HV009 fdw_invalid_use_of_null_pointer
HV014 fdw_too_many_handles
HV001 fdw_out_of_memory
HV00P fdw_no_schemas
HV00J fdw_option_name_not_found
HV00K fdw_reply_handle
HV00Q fdw_schema_not_found
HV00R fdw_table_not_found
HV00L fdw_unable_to_create_execution
HV00M fdw_unable_to_create_reply
HV00N fdw_unable_to_establish_connection
Class P0 — PL/pgSQL Error
P0000 plpgsql_error
P0001 raise_exception
P0002 no_data_found
P0003 too_many_rows
P0004 assert_failure
Class XX — Internal Error
XX000 internal_error
XX001 data_corrupted
XX002 index_corrupted

I have a table address_all and it is inherited by several address tables. address_history inherits from parent table history_all and keeps current address information. I am creating new table which inherits address_all table and copies information from address_history to new table.

My stored procedure is like this below. I am having some error when I call it. To better explain error I am using line number.

1  CREATE OR REPLACE FUNCTION somefunc()
2  RETURNS void AS
3  $BODY$
4  DECLARE
5   year_id INTEGER;
6   month_id INTEGER;
7   week_id INTEGER;
8   addresstablename text; 
9   backupdays text;
10 BEGIN
11  week_id := EXTRACT(DAY FROM TIMESTAMP 'now()');
12  month_id := EXTRACT(MONTH FROM TIMESTAMP 'now()');
13  year_id := EXTRACT(YEAR FROM TIMESTAMP 'now()');
14  addresstablename := 'address_history_' || week_id || '_' || month_id || '_' || year_id;
15  backupdays:= date_trunc('hour',CURRENT_TIMESTAMP - interval '7 days');
16  EXECUTE 'create table ' || addresstablename || '() INHERITS (address_all)';
17  EXECUTE 'insert into ' || addresstablename || ' select * from address_history where address_timestamp >= ' || backupdays || ''; --AS timestamp without time zone);  
18 END;
19 $BODY$
20 LANGUAGE 'plpgsql' VOLATILE;

When I run:

select somefunc()

I get this error:

ERROR:  syntax error at or near "12"
LINE 1: ...story where address_timestamp >= 2012-07-31 12:00:00-0...
                                                         ^
QUERY:  insert into address_history_7_8_2012 select * from address_history where address_timestamp >= 2012-07-31 12:00:00-04
CONTEXT:  PL/pgSQL function "somefunc" line 14 at EXECUTE statement

 ********** Error **********

ERROR: syntax error at or near "12"
SQL state: 42601
Context: PL/pgSQL function "somefunc" line 14 at EXECUTE statement

Erwin Brandstetter's user avatar

asked Aug 7, 2012 at 16:24

prakashpoudel's user avatar

Try this largely simplified form:

CREATE OR REPLACE FUNCTION somefunc()
  RETURNS void AS
$func$
DECLARE
 addresstablename text := 'address_history_' || to_char(now(), 'FMDD_MM_YYYY');

BEGIN
 EXECUTE 
 'CREATE TABLE ' || addresstablename || '() INHERITS (address_all)';

 EXECUTE
 'INSERT INTO ' || addresstablename || '
  SELECT *
  FROM   address_history
  WHERE  address_timestamp >= $1'
 USING date_trunc('hour', now() - interval '7 days');

END
$func$ LANGUAGE plpgsql;

Major points:

  • You can assign variables in plpgsql at declaration time. Simplifies code.

  • Use to_char() to format your date. Much simpler.

  • now() and CURRENT_TIMESTAMP do the same.

  • Don’t quote 'now()', use now() (without quotes) if you want the current timestamp.

  • Use the USING clause with EXECUTE, so you don’t have to convert the timestamp to text and back — possibly running into quoting issues like you did. Faster, simpler, safer.

  • In LANGUAGE plpgsql, plpgsql is a keyword and should not be quoted.

  • You may want to check if the table already exists with CREATE TABLE IF NOT EXISTS, available since PostgreSQL 9.1.

answered Aug 7, 2012 at 17:05

Erwin Brandstetter's user avatar

Erwin BrandstetterErwin Brandstetter

595k144 gold badges1056 silver badges1214 bronze badges

1

Apparently you need to quote backupdays, or it is not seen as a string from where to parse a timestamp.

answered Aug 7, 2012 at 16:27

LSerni's user avatar

LSerniLSerni

55.3k10 gold badges65 silver badges107 bronze badges

0

You’re building SQL using string manipulation so you have to properly quote everything just like in any other language. There are a few functions that you’ll want to know about:

  • quote_ident: quote an identifier such as a table name.
  • quote_literal: quote a string to use as a string literal.
  • quote_nullable: as quote_literal but properly handles NULLs as well.

Something like this will server you better:

EXECUTE 'create table ' || quote_ident(addresstablename) || ...
EXECUTE 'insert into '  || quote_ident(addresstablename) || ... || quote_literal(backupdays) ...

The quote_ident calls aren’t necessary in your case but they’re a good habit.

answered Aug 7, 2012 at 17:07

mu is too short's user avatar

mu is too shortmu is too short

425k70 gold badges829 silver badges795 bronze badges

5

Добрый вечер. Есть выражение:

$this->insertStmt = $this->connection->getPdo()->prepare("
    INSERT INTO files (
           real_name, 
           virtual_name, 
           album,
           size,
           resolution, 
           duration, 
           comment,
           path,
           user
    ) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)
");

Которое вызывается как обычно:

protected function doInsert(object $object)
{
    $values = [
        $object->getRealName(),
        $object->getVirtualName(),
        $object->getAlbum(),
        $object->getSize(),
        $object->getResolution(),
        $object->getDuration(),
        $object->getComment(),
        $object->getPath(),
        $object->getUser(),
    ];
       
    $this->insertStmt->execute($values);
}

Примерное содержание $values:

array(9) { 
    [0]=> string(15) "BvrK9z6UPxY.jpg" 
    [1]=> string(16) "1265dde1c67abc1c" 
    [2]=> string(23) "По умолчанию" 
    [3]=> int(54973) 
    [4]=> string(7) "720x430" 
    [5]=> NULL 
    [6]=> string(0) "" 
    [7]=> string(108) "files/id5cd487313a93a/По умолчанию/2019-05-10/1265dde1c67abc1c.jpg" 
    [8]=> string(15) "id5cd487313a93a" 
}

Сообщение ошибки:

Type: PDOException
Code: 42601
Message: SQLSTATE[42601]: Syntax error: 7 ОШИБКА: ошибка синтаксиса (примерное положение: "user") LINE 11: user ^

С точки зрения синтаксиса вроде все верно, много раз перепроверил, IDE ни на что не ругается. В чем трабл, господа?

Syntax errors are quite common while coding.

But, things go for a toss when it results in website errors.

PostgreSQL error 42601 also occurs due to syntax errors in the database queries.

At Bobcares, we often get requests from PostgreSQL users to fix errors as part of our Server Management Services.

Today, let’s check PostgreSQL error in detail and see how our Support Engineers fix it for the customers.

What causes error 42601 in PostgreSQL?

PostgreSQL is an advanced database engine. It is popular for its extensive features and ability to handle complex database situations.

Applications like Instagram, Facebook, Apple, etc rely on the PostgreSQL database.

But what causes error 42601?

PostgreSQL error codes consist of five characters. The first two characters denote the class of errors. And the remaining three characters indicate a specific condition within that class.

Here, 42 in 42601 represent the class “Syntax Error or Access Rule Violation“.

In short, this error mainly occurs due to the syntax errors in the queries executed. A typical error shows up as:

Here, the syntax error has occurred in position 119 near the value “parents” in the query.

How we fix the error?

Now let’s see how our PostgreSQL engineers resolve this error efficiently.

Recently, one of our customers contacted us with this error. He tried to execute the following code,

CREATE OR REPLACE FUNCTION prc_tst_bulk(sql text)
RETURNS TABLE (name text, rowcount integer) AS
$$
BEGIN
WITH m_ty_person AS (return query execute sql)
select name, count(*) from m_ty_person where name like '%a%' group by name
union
select name, count(*) from m_ty_person where gender = 1 group by name;
END
$$ LANGUAGE plpgsql;

But, this ended up in PostgreSQL error 42601. And he got the following error message,

ERROR: syntax error at or near "return"
LINE 5: WITH m_ty_person AS (return query execute sql)

Our PostgreSQL Engineers checked the issue and found out the syntax error. The statement in Line 5 was a mix of plain and dynamic SQL. In general, the PostgreSQL query should be either fully dynamic or plain. Therefore, we changed the code as,

RETURN QUERY EXECUTE '
WITH m_ty_person AS (' || sql || $x$)
SELECT name, count(*)::int FROM m_ty_person WHERE name LIKE '%a%' GROUP BY name
UNION
SELECT name, count(*)::int FROM m_ty_person WHERE gender = 1 GROUP BY name$x$;

This resolved the error 42601, and the code worked fine.

[Need more assistance to solve PostgreSQL error 42601?- We’ll help you.]

Conclusion

In short, PostgreSQL error 42601 occurs due to the syntax errors in the code. Today, in this write-up, we have discussed how our Support Engineers fixed this error for our customers.

PREVENT YOUR SERVER FROM CRASHING!

Never again lose customers to poor server speed! Let us help you.

Our server experts will monitor & maintain your server 24/7 so that it remains lightning fast and secure.

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var google_conversion_label = «owonCMyG5nEQ0aD71QM»;

восстановить базу из дампа:

-- -- PostgreSQL database dump -- -- Dumped from database version 10.19 (Ubuntu 10.19-0ubuntu0.18.04.1) -- Dumped by pg_dump version 10.19 (Ubuntu 10.19-0ubuntu0.18.04.1) SET statement_timeout = 0; SET lock_timeout = 0; SET idle_in_transaction_session_timeout = 0; SET client_encoding = 'UTF8'; SET standard_conforming_strings = on; SELECT pg_catalog.set_config('search_path', '', false); SET check_function_bodies = false; SET xmloption = content; SET client_min_messages = warning; SET row_security = off; -- -- Name: plpgsql; Type: EXTENSION; Schema: -; Owner: -- CREATE EXTENSION IF NOT EXISTS plpgsql WITH SCHEMA pg_catalog; -- -- Name: EXTENSION plpgsql; Type: COMMENT; Schema: -; Owner: -- COMMENT ON EXTENSION plpgsql IS 'PL/pgSQL procedural language'; -- -- Name: attribute_id_seq; Type: SEQUENCE; Schema: public; Owner: bender -- CREATE SEQUENCE public.attribute_id_seq START WITH 1 INCREMENT BY 1 NO MINVALUE NO MAXVALUE CACHE 1; ALTER TABLE public.attribute_id_seq OWNER TO bender; SET default_tablespace = ''; SET default_with_oids = false; -- -- Name: attribute; Type: TABLE; Schema: public; Owner: bender -- CREATE TABLE public.attribute ( attribute_id integer DEFAULT nextval('public.attribute_id_seq'::regclass) NOT NULL, name character varying(30) NOT NULL, attribute_type_id integer NOT NULL ); ALTER TABLE public.attribute OWNER TO bender; -- -- Name: attribute_type_id_seq; Type: SEQUENCE; Schema: public; Owner: bender -- CREATE SEQUENCE public.attribute_type_id_seq START WITH 1 INCREMENT BY 1 NO MINVALUE NO MAXVALUE CACHE 1; ALTER TABLE public.attribute_type_id_seq OWNER TO bender; -- -- Name: attribute_type; Type: TABLE; Schema: public; Owner: bender -- CREATE TABLE public.attribute_type ( attribute_type_id integer DEFAULT nextval('public.attribute_type_id_seq'::regclass) NOT NULL, name character varying(50) NOT NULL ); ALTER TABLE public.attribute_type OWNER TO bender; -- -- Name: film_id_seq; Type: SEQUENCE; Schema: public; Owner: bender -- CREATE SEQUENCE public.film_id_seq START WITH 1 INCREMENT BY 1 NO MINVALUE NO MAXVALUE CACHE 1; ALTER TABLE public.film_id_seq OWNER TO bender; -- -- Name: film; Type: TABLE; Schema: public; Owner: bender -- CREATE TABLE public.film ( film_id integer DEFAULT nextval('public.film_id_seq'::regclass) NOT NULL, name character varying(50) NOT NULL ); ALTER TABLE public.film OWNER TO bender; -- -- Name: film_attributes_id_seq; Type: SEQUENCE; Schema: public; Owner: bender -- CREATE SEQUENCE public.film_attributes_id_seq START WITH 1 INCREMENT BY 1 NO MINVALUE NO MAXVALUE CACHE 1; ALTER TABLE public.film_attributes_id_seq OWNER TO bender; -- -- Name: film_attributes; Type: TABLE; Schema: public; Owner: bender -- CREATE TABLE public.film_attributes ( film_attributes_id integer DEFAULT nextval('public.film_attributes_id_seq'::regclass) NOT NULL, attribute_id integer NOT NULL, film_id integer NOT NULL, value_text character varying, value_integer integer, value_float double precision, value_boolean boolean, value_timestamp timestamp with time zone ); ALTER TABLE public.film_attributes OWNER TO bender; -- -- Name: film_attributes_values; Type: VIEW; Schema: public; Owner: bender -- CREATE VIEW public.film_attributes_values AS SELECT NULL::character varying(50) AS name, NULL::character varying(50) AS attribute_type, NULL::character varying(30) AS attribute_name, NULL::character varying AS attribute_value; ALTER TABLE public.film_attributes_values OWNER TO bender; -- -- Name: film_tasks; Type: VIEW; Schema: public; Owner: bender -- CREATE VIEW public.film_tasks AS SELECT NULL::character varying(50) AS name, NULL::character varying[] AS today_tasks, NULL::character varying[] AS twenty_days_tasks; ALTER TABLE public.film_tasks OWNER TO bender; -- -- Data for Name: attribute; Type: TABLE DATA; Schema: public; Owner: bender -- COPY public.attribute (attribute_id, name, attribute_type_id) FROM stdin; 1 Рецензии 3 3 Премия Оскар 2 4 Премия Ника 2 5 Премия Золотой Глобус 2 10 Описание фильма 3 11 Длительность (мин.) 1 12 Длительность проката (дней) 1 2 Рейтинг 7 6 Премьера в мире 6 7 Премьера в России 6 8 Старт продажи билетов 6 9 Старт проката 6 13 Окончание проката 6 . -- -- Data for Name: attribute_type; Type: TABLE DATA; Schema: public; Owner: bender -- COPY public.attribute_type (attribute_type_id, name) FROM stdin; 1 integer 2 boolean 3 text 4 date 5 numeric 6 timestamp 7 float . -- -- Data for Name: film; Type: TABLE DATA; Schema: public; Owner: bender -- COPY public.film (film_id, name) FROM stdin; 1 Spoiler-man: No Way 2 Matrix 4 . -- -- Data for Name: film_attributes; Type: TABLE DATA; Schema: public; Owner: bender -- COPY public.film_attributes (film_attributes_id, attribute_id, film_id, value_text, value_integer, value_float, value_boolean, value_timestamp) FROM stdin; 1 1 1 Годный фильм, распинаюсь про сюжет, пишу про игру актеров, все круто N N N N 2 1 2 Джон Уик уже не тот, сестры Вачовски сбрендили, полная фигня N N N N 5 3 1 f N N N N 7 6 2 N N N N 2021-12-10 00:00:00+03 9 7 2 N N N N 2021-12-30 00:00:00+03 10 8 1 N N N N 2021-12-10 00:00:00+03 11 8 2 N N N N 2021-12-07 00:00:00+03 12 12 1 N 21 N N N 13 12 2 N 14 N N N 14 9 1 N N N N 2021-12-15 00:00:00+03 15 9 2 N N N N 2021-12-15 00:00:00+03 16 13 1 N N N N 2022-01-04 00:00:00+03 17 13 2 N N N N 2022-01-04 00:00:00+03 18 3 2 t N N N N 6 6 1 N N N N 2021-12-15 00:00:00+03 8 7 1 N N N N 2022-01-04 00:00:00+03 . -- -- Name: attribute_id_seq; Type: SEQUENCE SET; Schema: public; Owner: bender -- SELECT pg_catalog.setval('public.attribute_id_seq', 13, true); -- -- Name: attribute_type_id_seq; Type: SEQUENCE SET; Schema: public; Owner: bender -- SELECT pg_catalog.setval('public.attribute_type_id_seq', 6, true); -- -- Name: film_attributes_id_seq; Type: SEQUENCE SET; Schema: public; Owner: bender -- SELECT pg_catalog.setval('public.film_attributes_id_seq', 18, true); -- -- Name: film_id_seq; Type: SEQUENCE SET; Schema: public; Owner: bender -- SELECT pg_catalog.setval('public.film_id_seq', 2, true); -- -- Name: attribute attribute_pkey; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.attribute ADD CONSTRAINT attribute_pkey PRIMARY KEY (attribute_id); -- -- Name: attribute_type attribute_type_name_key; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.attribute_type ADD CONSTRAINT attribute_type_name_key UNIQUE (name); -- -- Name: attribute_type attribute_type_pkey; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.attribute_type ADD CONSTRAINT attribute_type_pkey PRIMARY KEY (attribute_type_id); -- -- Name: attribute attribute_unq; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.attribute ADD CONSTRAINT attribute_unq UNIQUE (name); -- -- Name: film_attributes film_attributes_pkey; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.film_attributes ADD CONSTRAINT film_attributes_pkey PRIMARY KEY (film_attributes_id); -- -- Name: film film_pkey; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.film ADD CONSTRAINT film_pkey PRIMARY KEY (film_id); -- -- Name: film film_unq; Type: CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.film ADD CONSTRAINT film_unq UNIQUE (name); -- -- Name: attribute_index; Type: INDEX; Schema: public; Owner: bender -- CREATE INDEX attribute_index ON public.attribute USING btree (name COLLATE "C.UTF-8" varchar_ops); -- -- Name: film_index; Type: INDEX; Schema: public; Owner: bender -- CREATE INDEX film_index ON public.film USING btree (name COLLATE "C.UTF-8"); -- -- Name: attribute attribute_type_fkey; Type: FK CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.attribute ADD CONSTRAINT attribute_type_fkey FOREIGN KEY (attribute_type_id) REFERENCES public.attribute_type(attribute_type_id) NOT VALID; -- -- Name: film_attributes film_attribute_attribute_fkey; Type: FK CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.film_attributes ADD CONSTRAINT film_attribute_attribute_fkey FOREIGN KEY (attribute_id) REFERENCES public.attribute(attribute_id); -- -- Name: film_attributes film_attribute_film_fkey; Type: FK CONSTRAINT; Schema: public; Owner: bender -- ALTER TABLE ONLY public.film_attributes ADD CONSTRAINT film_attribute_film_fkey FOREIGN KEY (film_id) REFERENCES public.film(film_id); -- -- PostgreSQL database dump complete --

ERROR: ОШИБКА:  ошибка синтаксиса (примерное положение: "1")
LINE 180: 1 Рецензии 3
^
SQL state: 42601
Character: 4115

Пользователь заполняет форму, где вводит значения в textBox-ы.

NpgsqlCommand com = new NpgsqlCommand("INSERT INTO 'Tip' (code_tip, 
name_tip) VALUES (@p1, @p2)", con);
com.Parameters.Add("code_tip", NpgsqlTypes.NpgsqlDbType.Bigint).Value = 
textBox1;
com.Parameters.Add("name_tip", NpgsqlTypes.NpgsqlDbType.Char, 40).Value = 
textBox2;
com.ExecuteNonQuery();

На этом моменте visual-studio выдает мне ошибку:

Npgsql.NpgsqlException: "ОШИБКА: 42601: ошибка синтаксиса (примерное положение: "'Tip'")"

Подскажите, что не так?

задан 21 сен 2018 в 11:03

Александр's user avatar

INSERT INTO ‘Tip’

По синтаксису (и стандарту SQL) insert запроса после ключевого слова into должно идти имя таблицы. Вы указали строковой литерал. Парсер соответственно удивляется и отвечает, что вы написали непонятно что.

  • в одинарных кавычках 'Tip' — строковой литерал.
  • без кавычек Tip — имя объекта, принудительно приводимое парсером к нижнему регистру, т.е. tip
  • в двойных кавычках "Tip" — регистрозависимое имя объекта

Если у вас таблица именно Tip, то единственным корректным способом к ней обращаться будут двойные кавычки:

INSERT INTO "Tip" ...

ответ дан 21 сен 2018 в 11:56

Мелкий's user avatar

МелкийМелкий

20.8k3 золотых знака26 серебряных знаков52 бронзовых знака

6

Содержание

  1. PostgreSQL error 42601- How we fix it
  2. What causes error 42601 in PostgreSQL?
  3. How we fix the error?
  4. Conclusion
  5. PREVENT YOUR SERVER FROM CRASHING!
  6. 10 Comments

PostgreSQL error 42601- How we fix it

by Sijin George | Sep 12, 2019

Syntax errors are quite common while coding.

But, things go for a toss when it results in website errors.

PostgreSQL error 42601 also occurs due to syntax errors in the database queries.

At Bobcares, we often get requests from PostgreSQL users to fix errors as part of our Server Management Services.

Today, let’s check PostgreSQL error in detail and see how our Support Engineers fix it for the customers.

What causes error 42601 in PostgreSQL?

PostgreSQL is an advanced database engine. It is popular for its extensive features and ability to handle complex database situations.

Applications like Instagram, Facebook, Apple, etc rely on the PostgreSQL database.

But what causes error 42601?

PostgreSQL error codes consist of five characters. The first two characters denote the class of errors. And the remaining three characters indicate a specific condition within that class.

Here, 42 in 42601 represent the class “Syntax Error or Access Rule Violation“.

In short, this error mainly occurs due to the syntax errors in the queries executed. A typical error shows up as:

Here, the syntax error has occurred in position 119 near the value “parents” in the query.

How we fix the error?

Now let’s see how our PostgreSQL engineers resolve this error efficiently.

Recently, one of our customers contacted us with this error. He tried to execute the following code,

But, this ended up in PostgreSQL error 42601. And he got the following error message,

Our PostgreSQL Engineers checked the issue and found out the syntax error. The statement in Line 5 was a mix of plain and dynamic SQL. In general, the PostgreSQL query should be either fully dynamic or plain. Therefore, we changed the code as,

This resolved the error 42601, and the code worked fine.

[Need more assistance to solve PostgreSQL error 42601?- We’ll help you.]

Conclusion

In short, PostgreSQL error 42601 occurs due to the syntax errors in the code. Today, in this write-up, we have discussed how our Support Engineers fixed this error for our customers.

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SELECT * FROM long_term_prediction_anomaly WHERE + “‘Timestamp’” + ‘”BETWEEN ‘” +
2019-12-05 09:10:00+ ‘”AND’” + 2019-12-06 09:10:00 + “‘;”)

Hello Joe,
Do you still get PostgreSQL errors? If you need help, we’ll be happy to talk to you on chat (click on the icon at right-bottom).

У меня ошибка drop table exists “companiya”;

CREATE TABLE “companiya” (
“compania_id” int4 NOT NULL,
“fio vladelca” text NOT NULL,
“name” text NOT NULL,
“id_operator” int4 NOT NULL,
“id_uslugi” int4 NOT NULL,
“id_reklama” int4 NOT NULL,
“id_tex-specialist” int4 NOT NULL,
“id_filial” int4 NOT NULL,
CONSTRAINT “_copy_8” PRIMARY KEY (“compania_id”)
);

CREATE TABLE “filial” (
“id_filial” int4 NOT NULL,
“street” text NOT NULL,
“house” int4 NOT NULL,
“city” text NOT NULL,
CONSTRAINT “_copy_5” PRIMARY KEY (“id_filial”)
);

CREATE TABLE “login” (
“id_name” int4 NOT NULL,
“name” char(20) NOT NULL,
“pass” char(20) NOT NULL,
PRIMARY KEY (“id_name”)
);

CREATE TABLE “operator” (
“id_operator” int4 NOT NULL,
“obrabotka obrasheniya” int4 NOT NULL,
“konsultirovanie” text NOT NULL,
“grafick work” date NOT NULL,
CONSTRAINT “_copy_2” PRIMARY KEY (“id_operator”)
);

CREATE TABLE “polsovateli” (
“id_user” int4 NOT NULL,
“id_companiya” int4 NOT NULL,
“id_obrasheniya” int4 NOT NULL,
“id_oshibka” int4 NOT NULL,
CONSTRAINT “_copy_6” PRIMARY KEY (“id_user”)
);

CREATE TABLE “reklama” (
“id_reklama” int4 NOT NULL,
“tele-marketing” text NOT NULL,
“soc-seti” text NOT NULL,
“mobile” int4 NOT NULL,
CONSTRAINT “_copy_3” PRIMARY KEY (“id_reklama”)
);

CREATE TABLE “tex-specialist” (
“id_tex-specialist” int4 NOT NULL,
“grafik” date NOT NULL,
“zarplata” int4 NOT NULL,
“ispravlenie oshibok” int4 NOT NULL,
CONSTRAINT “_copy_7” PRIMARY KEY (“id_tex-specialist”)
);

CREATE TABLE “uslugi” (
“id_uslugi” int4 NOT NULL,
“vostanavlenia parola” int4 NOT NULL,
“poterya acaunta” int4 NOT NULL,
CONSTRAINT “_copy_4” PRIMARY KEY (“id_uslugi”)
);

ALTER TABLE “companiya” ADD CONSTRAINT “fk_companiya_operator_1” FOREIGN KEY (“id_operator”) REFERENCES “operator” (“id_operator”);
ALTER TABLE “companiya” ADD CONSTRAINT “fk_companiya_uslugi_1” FOREIGN KEY (“id_uslugi”) REFERENCES “uslugi” (“id_uslugi”);
ALTER TABLE “companiya” ADD CONSTRAINT “fk_companiya_filial_1” FOREIGN KEY (“id_filial”) REFERENCES “filial” (“id_filial”);
ALTER TABLE “companiya” ADD CONSTRAINT “fk_companiya_reklama_1” FOREIGN KEY (“id_reklama”) REFERENCES “reklama” (“id_reklama”);
ALTER TABLE “companiya” ADD CONSTRAINT “fk_companiya_tex-specialist_1” FOREIGN KEY (“id_tex-specialist”) REFERENCES “tex-specialist” (“id_tex-specialist”);
ALTER TABLE “polsovateli” ADD CONSTRAINT “fk_polsovateli_companiya_1” FOREIGN KEY (“id_companiya”) REFERENCES “companiya” (“compania_id”);

ERROR: ОШИБКА: ошибка синтаксиса (примерное положение: “”companiya””)
LINE 1: drop table exists “companiya”;
^

Источник

Здравствуйте! Довольно распространенный вопрос, находил решения, но все же компилятор выводит ошибку. Как-то неправильно задаю первичный ключ.

Использую Postgresql

Java
1 2 3 4 5 6 7 8 9 10 11 12 
@Entity @Table(name="users") public class Users{     @Id     @GeneratedValue(strategy=GenerationType.IDENTITY)     @Column(columnDefinition="serial")     private Long id;     @Column(name="login")     private String login;     @Column(name="password")     private String password; }
SQL
1 2 3 4 5 
CREATE TABLE IF NOT EXISTS users (   id  SERIAL PRIMARY KEY NOT NULL,   login VARCHAR(20) UNIQUE NOT NULL,   password VARCHAR(20) NOT NULL );

Ошибка:
org.hibernate.tool.schema.spi.CommandAcceptanceExc eption: Error executing DDL via JDBC Statement
Caused by: org.postgresql.util.PSQLException: ОШИБКА: ошибка синтаксиса (примерное положение: «auto_increment»)

Добавлено через 27 минут
SQL-запрос пишу в консоли postgresql. Таблица без записей.
Также в проекте имеется обычный конфигурационный файл для JPA. Думаю, что роли он здесь не играет

__________________
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@YohDeadfall — I understand that part about it, but this is not script that I am creating or even code that I am creating. This is all created under the hood by Npsql/EntityFramework. My quick guess is that I am extending my DbContext from IdentityDbContext<IdentityUser> which wants to create all of the tables for roles, users, claims, etc. If I change this to just extend from DbContext, then everything works as advertised.

Below is the script that EF is trying to use created from dotnet ef migrations script — please be aware that I have removed my custom part of the script for brevity.

You can see there are two specific calls that are being made where [NormalizedName] and [NormalizedUserName] are being used.

CREATE TABLE IF NOT EXISTS "__EFMigrationsHistory" ( "MigrationId" varchar(150) NOT NULL, "ProductVersion" varchar(32) NOT NULL, CONSTRAINT "PK___EFMigrationsHistory" PRIMARY KEY ("MigrationId") ); CREATE TABLE "AspNetRoles" ( "Id" text NOT NULL, "ConcurrencyStamp" text NULL, "Name" varchar(256) NULL, "NormalizedName" varchar(256) NULL, CONSTRAINT "PK_AspNetRoles" PRIMARY KEY ("Id") ); CREATE TABLE "AspNetUsers" ( "Id" text NOT NULL, "AccessFailedCount" int4 NOT NULL, "ConcurrencyStamp" text NULL, "Email" varchar(256) NULL, "EmailConfirmed" bool NOT NULL, "LockoutEnabled" bool NOT NULL, "LockoutEnd" timestamptz NULL, "NormalizedEmail" varchar(256) NULL, "NormalizedUserName" varchar(256) NULL, "PasswordHash" text NULL, "PhoneNumber" text NULL, "PhoneNumberConfirmed" bool NOT NULL, "SecurityStamp" text NULL, "TwoFactorEnabled" bool NOT NULL, "UserName" varchar(256) NULL, CONSTRAINT "PK_AspNetUsers" PRIMARY KEY ("Id") ); CREATE TABLE "AspNetRoleClaims" ( "Id" int4 NOT NULL, "ClaimType" text NULL, "ClaimValue" text NULL, "RoleId" text NOT NULL, CONSTRAINT "PK_AspNetRoleClaims" PRIMARY KEY ("Id"), CONSTRAINT "FK_AspNetRoleClaims_AspNetRoles_RoleId" FOREIGN KEY ("RoleId") REFERENCES "AspNetRoles" ("Id") ON DELETE CASCADE ); CREATE TABLE "AspNetUserClaims" ( "Id" int4 NOT NULL, "ClaimType" text NULL, "ClaimValue" text NULL, "UserId" text NOT NULL, CONSTRAINT "PK_AspNetUserClaims" PRIMARY KEY ("Id"), CONSTRAINT "FK_AspNetUserClaims_AspNetUsers_UserId" FOREIGN KEY ("UserId") REFERENCES "AspNetUsers" ("Id") ON DELETE CASCADE ); CREATE TABLE "AspNetUserLogins" ( "LoginProvider" text NOT NULL, "ProviderKey" text NOT NULL, "ProviderDisplayName" text NULL, "UserId" text NOT NULL, CONSTRAINT "PK_AspNetUserLogins" PRIMARY KEY ("LoginProvider", "ProviderKey"), CONSTRAINT "FK_AspNetUserLogins_AspNetUsers_UserId" FOREIGN KEY ("UserId") REFERENCES "AspNetUsers" ("Id") ON DELETE CASCADE ); CREATE TABLE "AspNetUserRoles" ( "UserId" text NOT NULL, "RoleId" text NOT NULL, CONSTRAINT "PK_AspNetUserRoles" PRIMARY KEY ("UserId", "RoleId"), CONSTRAINT "FK_AspNetUserRoles_AspNetRoles_RoleId" FOREIGN KEY ("RoleId") REFERENCES "AspNetRoles" ("Id") ON DELETE CASCADE, CONSTRAINT "FK_AspNetUserRoles_AspNetUsers_UserId" FOREIGN KEY ("UserId") REFERENCES "AspNetUsers" ("Id") ON DELETE CASCADE ); CREATE TABLE "AspNetUserTokens" ( "UserId" text NOT NULL, "LoginProvider" text NOT NULL, "Name" text NOT NULL, "Value" text NULL, CONSTRAINT "PK_AspNetUserTokens" PRIMARY KEY ("UserId", "LoginProvider", "Name"), CONSTRAINT "FK_AspNetUserTokens_AspNetUsers_UserId" FOREIGN KEY ("UserId") REFERENCES "AspNetUsers" ("Id") ON DELETE CASCADE ); CREATE INDEX "IX_AspNetRoleClaims_RoleId" ON "AspNetRoleClaims" ("RoleId"); CREATE UNIQUE INDEX "RoleNameIndex" ON "AspNetRoles" ("NormalizedName") WHERE [NormalizedName] IS NOT NULL; CREATE INDEX "IX_AspNetUserClaims_UserId" ON "AspNetUserClaims" ("UserId"); CREATE INDEX "IX_AspNetUserLogins_UserId" ON "AspNetUserLogins" ("UserId"); CREATE INDEX "IX_AspNetUserRoles_RoleId" ON "AspNetUserRoles" ("RoleId"); CREATE INDEX "EmailIndex" ON "AspNetUsers" ("NormalizedEmail"); CREATE UNIQUE INDEX "UserNameIndex" ON "AspNetUsers" ("NormalizedUserName") WHERE [NormalizedUserName] IS NOT NULL; INSERT INTO "__EFMigrationsHistory" ("MigrationId", "ProductVersion") VALUES ('20180514204732_initial', '2.0.3-rtm-10026');

Перейти к содержимому

pg_dump — это программа для создания резервных копий базы данных Postgres Pro.

При попытке восстановления дампа под Windopws 7 столкнулся с ошибкой:

COPY carriers (business_entity_id, name) FROM stdin;
8	Arriva
50000	ASEAG
.

[Err] ОШИБКА: ошибка синтаксиса (примерное положение: «8»)
LINE 2: 8 Arriva
^

Мы получаем простую синтаксическую ошибку, потому что Postgres получает данные как код SQL.

Пример ниже не поддерживается утилитой pgAdmin.

COPY tablel FROM STDIN;

Как сделать резервную копию базы в Postgress?

pg_dump -U user database > fileName.sql

где:

  • pg_dump это программа для создания резервных копий базы данных Postgres Pro;
  • postgres — имя пользователя БД (совпадает с именем базы данных);
  • transactions — имя базы к которой есть доступ у нашего пользователя postgres;
  • transactions.sql — имя создаваемого файла дампа;
  • hostname — имя сервера БД, это pg.sweb.ru;
  • format — формат дампа (может быть одной из трех букв: ‘с’ (custom — архив .tar.gz), ‘t’ (tar — tar-файл), ‘p’ (plain — текстовый файл). В команде букву надо указывать без кавычек.);
  • dbname — имя базы данных.
pg_dump -U postgres transactions > transactions.sql

Как сделать restore в Postgress?

Тут все несколько запутанней, поэтому выкладываю все 3 варианта начну с того который решил мою проблему:

psql -U postgres -d belgianbeers -a -f beers.sql

pg_restore -h localhost -U postgres -F t -d transactions «D:/transactions.sql»

pg_restore —host localhost —port 5432 —username postgres —dbname transactions —clean —verbose «D:transactions.sql»

Не забывайте если указываете полный путь брать его в двойные кавычки!!!

when I am using this command to update table in PostgreSQL 13:

UPDATE rss_sub_source 
SET sub_url = SUBSTRING(sub_url, 1, CHAR_LENGTH(sub_url) - 1) 
WHERE sub_url LIKE '%/'
limit 10

but shows this error:

SQL Error [42601]: ERROR: syntax error at or near "limit"
Position: 111

why would this error happen and what should I do to fix it?

asked Jul 22, 2021 at 14:09

Dolphin's user avatar

1

LIMIT isn’t a valid keyword in an UPDATE statement according to the official PostgreSQL documentation:

[ WITH [ RECURSIVE ] with_query [, ...] ]
UPDATE [ ONLY ] table_name [ * ] [ [ AS ] alias ]
SET { column_name = { expression | DEFAULT } |
( column_name [, ...] ) = [ ROW ] ( { expression | DEFAULT } [, ...] ) |
( column_name [, ...] ) = ( sub-SELECT )
} [, ...]
[ FROM from_item [, ...] ]
[ WHERE condition | WHERE CURRENT OF cursor_name ]
[ RETURNING * | output_expression [ [ AS ] output_name ] [, ...] ]

Reference: UPDATE (PostgreSQL Documentation )

Solution

Remove LIMIT 10 from your statement.

a_horse_with_no_name's user avatar

answered Jul 22, 2021 at 14:32

John K. N.'s user avatar

John K. N.John K. N.

15.7k10 gold badges45 silver badges100 bronze badges

0

You could make something like this

But a Limit without an ORDER BY makes no sense, so you must choose one that gets you the correct 10 rows

UPDATE rss_sub_source t1
SET t1.sub_url = SUBSTRING(t1.sub_url, 1, CHAR_LENGTH(t1.sub_url) - 1) 
FROM (SELECT id FROM rss_sub_source WHERE sub_url LIKE '%/' ORDER BY id LIMIT 10) t2 
WHERE t2.id = t1.id

answered Jul 22, 2021 at 14:51

nbk's user avatar

nbknbk

7,7295 gold badges12 silver badges27 bronze badges

when I am using this command to update table in PostgreSQL 13:

UPDATE rss_sub_source SET sub_url = SUBSTRING(sub_url, 1, CHAR_LENGTH(sub_url) - 1) WHERE sub_url LIKE '%/' limit 10 

but shows this error:

SQL Error [42601]: ERROR: syntax error at or near "limit" Position: 111 

why would this error happen and what should I do to fix it?

asked Jul 22, 2021 at 14:09

Dolphin's user avatar

1

LIMIT isn’t a valid keyword in an UPDATE statement according to the official PostgreSQL documentation:

[ WITH [ RECURSIVE ] with_query [, ...] ]
UPDATE [ ONLY ] table_name [ * ] [ [ AS ] alias ]
SET { column_name = { expression | DEFAULT } |
( column_name [, ...] ) = [ ROW ] ( { expression | DEFAULT } [, ...] ) |
( column_name [, ...] ) = ( sub-SELECT )
} [, ...]
[ FROM from_item [, ...] ]
[ WHERE condition | WHERE CURRENT OF cursor_name ]
[ RETURNING * | output_expression [ [ AS ] output_name ] [, ...] ]

Reference: UPDATE (PostgreSQL Documentation )

Solution

Remove LIMIT 10 from your statement.

a_horse_with_no_name's user avatar

answered Jul 22, 2021 at 14:32

John K. N.'s user avatar

John K. N.John K. N.

15.7k10 gold badges45 silver badges100 bronze badges

0

You could make something like this

But a Limit without an ORDER BY makes no sense, so you must choose one that gets you the correct 10 rows

UPDATE rss_sub_source t1
SET t1.sub_url = SUBSTRING(t1.sub_url, 1, CHAR_LENGTH(t1.sub_url) - 1) 
FROM (SELECT id FROM rss_sub_source WHERE sub_url LIKE '%/' ORDER BY id LIMIT 10) t2 
WHERE t2.id = t1.id

answered Jul 22, 2021 at 14:51

nbk's user avatar

nbknbk

7,7295 gold badges12 silver badges27 bronze badges

when I am using this command to update table in PostgreSQL 13:

UPDATE rss_sub_source 
SET sub_url = SUBSTRING(sub_url, 1, CHAR_LENGTH(sub_url) - 1) 
WHERE sub_url LIKE '%/'
limit 10

but shows this error:

SQL Error [42601]: ERROR: syntax error at or near "limit"
  Position: 111

why would this error happen and what should I do to fix it?

asked Jul 22, 2021 at 14:09

Dolphin's user avatar

1

LIMIT isn’t a valid keyword in an UPDATE statement according to the official PostgreSQL documentation:

[ WITH [ RECURSIVE ] with_query [, ...] ]
UPDATE [ ONLY ] table_name [ * ] [ [ AS ] alias ]
    SET { column_name = { expression | DEFAULT } |
          ( column_name [, ...] ) = [ ROW ] ( { expression | DEFAULT } [, ...] ) |
          ( column_name [, ...] ) = ( sub-SELECT )
        } [, ...]
    [ FROM from_item [, ...] ]
    [ WHERE condition | WHERE CURRENT OF cursor_name ]
    [ RETURNING * | output_expression [ [ AS ] output_name ] [, ...] ]

Reference: UPDATE (PostgreSQL Documentation )

Solution

Remove LIMIT 10 from your statement.

a_horse_with_no_name's user avatar

answered Jul 22, 2021 at 14:32

John K. N.'s user avatar

John K. N.John K. N.

16.6k10 gold badges47 silver badges106 bronze badges

0

You could make something like this

But a Limit without an ORDER BY makes no sense, so you must choose one that gets you the correct 10 rows

UPDATE rss_sub_source t1
SET t1.sub_url = SUBSTRING(t1.sub_url, 1, CHAR_LENGTH(t1.sub_url) - 1) 
FROM (SELECT id FROM rss_sub_source WHERE sub_url LIKE '%/' ORDER BY id LIMIT 10) t2 
WHERE t2.id = t1.id

answered Jul 22, 2021 at 14:51

nbk's user avatar

nbknbk

7,8435 gold badges12 silver badges27 bronze badges

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