Given the following:
a = 23
b = 45
c = 16
round((a/b)*0.9*c)
Running the above outputs an error:
TypeError: 'int' object is not callable.
How can I round the output to an integer?
Mateen Ulhaq
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asked Mar 19, 2012 at 9:05
2
Somewhere else in your code you have something that looks like this:
round = 42
Then when you write
round((a/b)*0.9*c)
that is interpreted as meaning a function call on the object bound to round
, which is an int
. And that fails.
The problem is whatever code binds an int
to the name round
. Find that and remove it.
answered Mar 19, 2012 at 9:08
David HeffernanDavid Heffernan
599k42 gold badges1064 silver badges1482 bronze badges
2
I got the same error (TypeError: ‘int’ object is not callable)
def xlim(i,k,s1,s2):
x=i/(2*k)
xl=x*(1-s2*x-s1*(1-x)) / (1-s2*x**2-2*s1*x(1-x))
return xl
... ... ... ...
>>> xlim(1,100,0,0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in xlim
TypeError: 'int' object is not callable
after reading this post I realized that I forgot a multiplication sign * so
def xlim(i,k,s1,s2):
x=i/(2*k)
xl=x*(1-s2*x-s1*(1-x)) / (1-s2*x**2-2*s1*x * (1-x))
return xl
xlim(1.0,100.0,0.0,0.0)
0.005
tanks
answered Jul 17, 2015 at 18:45
TomateTomate
1951 silver badge5 bronze badges
3
Stop stomping on round
somewhere else by binding an int
to it.
answered Mar 19, 2012 at 9:07
0
I was also facing this issue but in a little different scenario.
Scenario:
param = 1
def param():
.....
def func():
if param:
var = {passing a dict here}
param(var)
It looks simple and a stupid mistake here, but due to multiple lines of codes in the actual code, it took some time for me to figure out that the variable name I was using was same as my function name because of which I was getting this error.
Changed function name to something else and it worked.
So, basically, according to what I understood, this error means that you are trying to use an integer as a function or in more simple terms, the called function name is also used as an integer somewhere in the code.
So, just try to find out all occurrences of the called function name and look if that is being used as an integer somewhere.
I struggled to find this, so, sharing it here so that someone else may save their time, in case if they get into this issue.
answered Mar 4, 2020 at 12:04
0
In my case I changed:
return <variable>
with:
return str(<variable>)
try with the following and it must work:
str(round((a/b)*0.9*c))
eyllanesc
233k19 gold badges163 silver badges235 bronze badges
answered Apr 11, 2018 at 17:40
Sometimes the problem would be forgetting an operator while calculation.
Example:
print(n-(-1+(math.sqrt(1-4(2*(-n))))/2))
rather
it has to be
print(n-(-1+(math.sqrt(1-4*(2*(-n))))/2))
HTH
answered Jun 12, 2021 at 19:16
There are two reasons for this error «TypeError: ‘int’ object is not callable«
- Function Has an Integer Value
Consider
a = [5, 10, 15, 20]
max = 0
max = max(a)
print(max)
This will produce TypeError: ‘int’ object is not callable.
Just change the variable name «max» to var(say).
a = [5, 10, 15, 20]
var = 0
var = max(a)
print(var)
The above code will run perfectly without any error!!
- Missing a Mathematical Operator
Consider
a = 5
b = a(a+1)
print(b)
This will also produce TypeError: ‘int’ object is not callable.
You might have forgotten to put the operator in between ( ‘*’ in this case )
answered Jul 21, 2021 at 9:47
1
As mentioned you might have a variable named round (of type int
) in your code and removing that should get rid of the error. For Jupyter notebooks however, simply clearing a cell or deleting it might not take the variable out of scope. In such a case, you can restart your notebook to start afresh after deleting the variable.
answered Apr 10, 2020 at 13:20
krishnakeshankrishnakeshan
1,1922 gold badges13 silver badges18 bronze badges
You can always use the below method to disambiguate the function.
__import__('__builtin__').round((a/b)*0.9*c)
__builtin__
is the module name for all the built in functions like round, min, max etc. Use the appropriate module name for functions from other modules.
answered Sep 12, 2021 at 14:59
I encountered this error because I was calling a function inside my model that used the @property decorator.
@property
def volume_range(self):
return self.max_oz - self.min_oz
When I tried to call this method in my serializer, I hit the error «TypeError: ‘int’ object is not callable».
def get_oz_range(self, obj):
return obj.volume_range()
In short, the issue was that the @property decorator turns a function into a getter. You can read more about property() in this SO response.
The solution for me was to access volume_range like a variable and not call it as a function:
def get_oz_range(self, obj):
return obj.volume_range # No more parenthesis
answered Jun 25, 2022 at 20:54
BanjoeBanjoe
10.2k3 gold badges48 silver badges60 bronze badges
FYI: the 'int' object is not callable
error also appears if you accidentally use .size()
as a method (which does not exist) instead of the .size
property in Pandas dataframes as demonstrated below. Thus the error can appear in unexpected places.
import pandas as pd
s = pd.Series([35, 52, 63, 52])
print("unique numbers: ",s.unique())
print("number of unique values: ",s.unique().size())
answered May 15 at 14:09
In Python, a “Typeerror” occurs when you use different data types in an operation.
For example, if you attempt to divide an integer (number) by a string, it leads to a typeerror
because an integer data type is not the same as a string.
One of those type errors is the “int object is not callable” error.
The “int object is not callable” error occurs when you declare a variable and name it with a built-in function name such as int()
, sum()
, max()
, and others.
The error also occurs when you don’t specify an arithmetic operator while performing a mathematical operation.
In this article, I will show you how the error occurs and what you can do to fix it.
How to Fix Typeerror: int object is not callable
in Built-in Function Names
If you use a built-in function name as a variable and call it as a function, you’ll get the “int object is not callable” error.
For instance, the code below attempts to calculate the total ages of some kids with the built-in sum()
function of Python. The code resulted in an error because the same sum
has already been used as a variable name:
kid_ages = [2, 7, 5, 6, 3]
sum = 0
sum = sum(kid_ages)
print(sum)
Another example below shows how I tried to get the oldest within those kids with the max()
function, but I had declared a max
variable already:
kid_ages = [2, 7, 5, 6, 3]
max = 0
max = max(kid_ages)
print(max)
Both code examples led to this error in the terminal:
To fix the issue, you need to change the name of the variable you named as a built-in function so the code can run successfully:
kid_ages = [2, 7, 5, 6, 3]
sum_of_ages = 0
sum = sum(kid_ages)
print(sum)
# Output: 23
kid_ages = [2, 7, 5, 6, 3]
max_of_ages = 0
max = max(kid_ages)
print(max)
# Output: 7
If you get rid of the custom variables, your code will still run as expected:
kid_ages = [2, 7, 5, 6, 3]
sum = sum(kid_ages)
print(sum)
# Output: 23
kid_ages = [2, 7, 5, 6, 3]
max = max(kid_ages)
print(max)
# Output: 7
How to Fix Typeerror: int object is not callable
in Mathematical Calculations
In Mathematics, if you do something like 4(2+3), you’ll get the right answer which is 20. But in Python, this would lead to the Typeerror: int object is not callable
error.
To fix this error, you need to let Python know you want to multiply the number outside the parentheses with the sum of the numbers inside the parentheses.
To do this, you do this by specifying a multiplication sign (*) before the opening parenthesis:
print(4*(2+3))
#Output: 20
Python allows you to specify any arithmetic sign before the opening parenthesis.
So, you can perform other calculations there too:
print(4+(2+3))
# Output: 9
print(4-(2+3))
# Output: -1
print(4/(2+3))
# Output: 0.8
Final Thoughts
The Typeerror: int object is not callable
is a beginner error in Python you can avoid in a straightforward way.
As shown in this article, you can avoid the error by not using a built-in function name as a variable identifier and specifying arithmetic signs where necessary.
Thank you for reading.
Learn to code for free. freeCodeCamp’s open source curriculum has helped more than 40,000 people get jobs as developers. Get started
n = 24
if n % 2 == 0 (n >= 6 and n <= 20):
print("Weird")
…emits the error message:
TypeError: 'int' object is not callable
What does this mean? How can it be avoided?
Charles Duffy
277k43 gold badges380 silver badges436 bronze badges
asked Feb 11, 2020 at 0:15
6
You need the and
or or
operator to combine the modulus condition and the range condition.
Python also allows you to use chained comparisons to test if a number is in a range.
if n % 2 == 0 or 6 <= n <= 20:
answered Feb 11, 2020 at 0:19
BarmarBarmar
731k53 gold badges488 silver badges607 bronze badges
you are equating the division to 0 and the other condition all together.
you have to separate the steps, equal to zero and then check.
n = 24
if n % 2 == 0:
print («Not Weird»)
else:
print («Weird»)
if n % 2 == 0 & (n >= 6 and n <= 20):
print(«Weird»)
if n % 2 == 0 & (n <= 2 and n >= 5):
print(«Not Weird»)
if n % 2 == 0 & (n > 20):
print(«Not Weird»)
answered Feb 11, 2020 at 0:24
7
Table of Contents
Hide
- What is TypeError: the ‘int’ object is not callable?
- Scenario 1: When you try to call the reserved keywords as a function
- Solution
- Scenario 2: Missing an Arithmetic operator while performing the calculation
- Solution
- Conclusion
The TypeError: the ‘int’ object is not a callable error occurs if an arithmetic operator is missed while performing the calculations or the reserved keywords are declared as variables and used as functions,
In this tutorial, we will learn what int object is is not callable error means and how to resolve this TypeError in your program with examples.
There are two main scenarios where developers try to call an integer.
- When you try to call the reserved keywords as a function
- Missing an Arithmetic operator while performing the calculation
Scenario 1: When you try to call the reserved keywords as a function
Using the reserved keywords as variables and calling them as functions are developers’ most common mistakes when they are new to Python. Let’s take a simple example to reproduce this issue.
item_price = [10, 33, 55, 77]
sum = 0
sum = sum(item_price)
print("The sum of all the items is:", str(sum))
Output
Traceback (most recent call last):
File "c:PersonalIJSCodemain.py", line 4, in <module>
sum = sum(item_price)
TypeError: 'int' object is not callable
If you look at the above code, we have declared the sum as a variable. However, in Python, the sum()
is a reserved keyword and a built-in method that adds the items of an iterable and returns the sum.
Since we have declared sum as a variable and used it as a function to add all the items in the list, Python will throw TypeError.
Solution
We can fix this error by renaming the sum
variable to total_price
, as shown below.
item_price = [10, 33, 55, 77]
total_price = 0
total_price = sum(item_price)
print("The sum of all the items is:", str(total_price))
Output
The sum of all the items is: 175
Scenario 2: Missing an Arithmetic operator while performing the calculation
While performing mathematical calculations, if you miss an arithmetic operator within your code, it leads to TypeError: the ‘int’ object is not a callable error.
Let us take a simple example to calculate the tax for the order. In order to get the tax value, we need to multiply total_value*(tax_percentage/100)
.
item_price = [10, 23, 66, 45]
tax_percentage = 5
total_value = sum(item_price)
tax_value = total_value(5/100)
print(" The tax amount for the order is:", tax_value)
Output
Traceback (most recent call last):
File "c:PersonalIJSCodemain.py", line 8, in <module>
tax_value = total_value(5/100)
TypeError: 'int' object is not callable
We have missed out on the multiplication operator while calculating the tax value in our code, leading to TypeError by the Python interpreter.
Solution
We can fix this issue by adding a multiplication (*) operator to our code, as shown below.
item_price = [10, 23, 66, 45]
tax_percentage = 5
total_value = sum(item_price)
tax_value = total_value*(5/100)
print(" The tax amount for the order is:", tax_value)
Output
The tax amount for the order is: 7.2
Conclusion
The TypeError: the ‘int’ object is not a callable error raised when you try to call the reserved keywords as a function or miss an arithmetic operator while performing mathematical calculations.
Developers should keep the following points in mind to avoid the issue while coding.
- Use descriptive and unique variable names.
- Never use any built-in function, modules, reserved keywords as Python variable names.
- Ensure that arithmetic operators is not missed while performing calculations.
- Do not override built-in functions like
sum()
,round()
, and use the same methods later in your code to perform operations.
Srinivas Ramakrishna is a Solution Architect and has 14+ Years of Experience in the Software Industry. He has published many articles on Medium, Hackernoon, dev.to and solved many problems in StackOverflow. He has core expertise in various technologies such as Microsoft .NET Core, Python, Node.JS, JavaScript, Cloud (Azure), RDBMS (MSSQL), React, Powershell, etc.
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Error TypeError: ‘int’ object is not callable
This is a common coding error that occurs when you declare a variable with the same name as inbuilt int() function used in the code. Python compiler gets confused between variable ‘int’ and function int() because of their similar names and therefore throws typeerror: ‘int’ object is not callable error.
To overcome this problem, you must use unique names for custom functions and variables.
Example
##Error Code
#Declaring and Initializing a variable
int = 5;
#Taking input from user {Start}
productPrice = int(input("Enter the product price : "))
productQuantity = int(input("Enter the number of products : "))
#Taking input from user {Ends}
# variable to hold the value of effect on the balance sheet
# after purchasing this product.
costOnBalanceSheet = productPrice * productQuantity
#printing the output
print(costOnBalanceSheet)
Output
Enter the product price : 2300
Traceback (most recent call last):
File "C:UsersWebartsolAppDataLocalProgramsPythonPython37-32intObjectnotCallable.py", line 3, in <module>
productPrice = int(input("Enter the product price : "))
TypeError: 'int' object is not callable
In the example above we have declared a variable named `int` and later in the program, we have also used the Python inbuilt function int() to convert the user input into int values.
Python compiler takes “int” as a variable, not as a function due to which error “TypeError: ‘int’ object is not callable” occurs.
How to resolve typeerror: ‘int’ object is not callable
To resolve this error, you need to change the name of the variable whose name is similar to the in-built function int() used in the code.
#Code without error
#Declaring and Initializing a variable
productType = 5;
#Taking input from user {Start}
productPrice = int(input("Enter the product price : "))
productQuantity = int(input("Enter the number of products : "))
#Taking input from user {Ends}
# variable to hold the value of effect on the balance sheet
# after purchasing this product
costOnBalanceSheet = productPrice * productQuantity
#printing the output
print(costOnBalanceSheet)
OUTPUT:
Enter the product price : 3500
Enter the number of products : 23
80500
In the above example, we have just changed the name of variable “int” to “productType”.
How to avoid this error?
To avoid this error always keep the following points in your mind while coding:
- Use unique and descriptive variable names
- Do not use variable name same as python in-built function name, module name & constants
- Make the function names descriptive and use docstring to describe the function