Ошибка limit 0 50 sql - Не ошибается лишь тот, кто ничего не делает!

When I run this query:

SELECT * FROM `forums_posts` WHERE pid < IS NULL ORDER BY pid DESC LIMIT 0,50

MySQL version: 5.5.5-10.1.13-MariaDB

I receive this error:

Error: 1S111/1 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right
syntax to use near ‘IS NULL ORDER BY pid DESC LIMIT 0,50’ at line 1

What am I doing wrong?

kix

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asked Aug 29, 2016 at 9:23

The condition is IS NULL or IS NOT NULL. Don’t exist ‘pid< IS NULL’.

SELECT * FROM forums_posts WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50

answered Aug 29, 2016 at 9:31

If You want get record where pid is not null then Try This :

SELECT * FROM `forums_posts` WHERE pid IS NOT NULL ORDER BY pid DESC LIMIT 0,50

If You want get record where pid is null then Try This :

SELECT * FROM `forums_posts` WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50

We can not use < ,> also another this kind of operator with IS NULL.

answered Aug 29, 2016 at 9:28

Kumar RakeshKumar Rakesh

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Try this

SELECT * FROM table_name WHERE id IS NULL ORDER BY id DESC LIMIT 0,50

answered Aug 29, 2016 at 9:34

You use wrong query : pid < IS NULL is nothing.

Either it will be

 SELECT * FROM `forums_posts` WHERE pid IS NOT NULL ORDER BY pid DESC LIMIT 0,50 // if you don't want NULL value

SELECT * FROM `forums_posts` WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50 // if you want only NULL value

answered Aug 29, 2016 at 9:26

ManishManish

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SELECT * FROM `forums_posts` WHERE pid < IS NULL ORDER BY pid DESC LIMIT 0,50

It should be pid < IS NULL

Because In SQL Every Single NULL is different from the other NULL value.For that purpose, We can not use <, > as we would use for other.

answered Aug 29, 2016 at 9:27

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Link24

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03.10.2013, 20:01. Показов 3207. Ответов 7

Метки нет (Все метки)

Необходима выборка не более 50 значений

SQL

1
2
3

SELECT org, gorod, adres FROM org  WHERE org LIKE %colname% OR adres LIKE  %colname% OR gorod LIKE %colname%  LIMIT 0, 50 UNION  SELECT org2, gorod2, adres2
FROM g2
WHERE org2 LIKE %colname% OR adres2 LIKE  %colname% OR gorod2 LIKE %colname%  LIMIT 0, 50

В чем ошибка? мозг сломал
Всем авансом спасибо!!!

Programming

Эксперт

94731 / 64177 / 26122

Регистрация: 12.04.2006

Сообщений: 116,782

03.10.2013, 20:01

Ответы с готовыми решениями:

LIMIT
$result = mysql_query("SELECT * FROM table_reviews,table_one WHERE table_one.id_image =…

Limit
Есть ли в Accesse что-нибудь подобное Limit из
mySQL?

LIMIT
Есть таблица table с полями (ID_продукта | ID_магазина | цена_продукта)

Можно программно сделать…

LIMIT and WHERE
SELECT id, user, name
FROM classes AS cl
WHERE !del
ORDER BY last DESC
LIMIT {$f}, {$c}…

_ViPeR_

614 / 488 / 175

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Сообщений: 1,236

04.10.2013, 06:13

MySQL

(SELECT org, gorod, adres
FROM org 
WHERE org LIKE %colname% OR adres LIKE  %colname% OR gorod LIKE %colname%)
UNION
(SELECT org2, gorod2, adres2
FROM g2
WHERE org2 LIKE %colname% OR adres2 LIKE  %colname% OR gorod2 LIKE %colname%)
LIMIT 0, 50

Link24

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Регистрация: 18.04.2013

Сообщений: 117

04.10.2013, 16:03

[ТС]

Сообщение от _ViPeR_

MySQL

(SELECT org, gorod, adres
FROM org 
WHERE org LIKE %colname% OR adres LIKE  %colname% OR gorod LIKE %colname%)
UNION
(SELECT org2, gorod2, adres2
FROM g2
WHERE org2 LIKE %colname% OR adres2 LIKE  %colname% OR gorod2 LIKE %colname%)
LIMIT 0, 50

Дак запрос с select должен начинаться. Так не катит

2663 / 1727 / 175

Регистрация: 05.06.2011

Сообщений: 4,967

05.10.2013, 12:04

Сообщение от Link24

В чем ошибка?

Дык текст-то ошибки — где?
Навскидку — а разве строки в кавычки не надо брать? MySQL подзабыл уже.

Link24

0 / 0 / 0

Регистрация: 18.04.2013

Сообщений: 117

06.10.2013, 12:27

[ТС]

Сообщение от iifat

Дык текст-то ошибки — где?
Навскидку — а разве строки в кавычки не надо брать? MySQL подзабыл уже.

SQL

(SELECT org, gorod, adres
FROM org 
WHERE org LIKE %colname% OR adres LIKE  %colname% OR gorod LIKE %colname%)
UNION
(SELECT org2, gorod2, adres2
FROM g2
WHERE org2 LIKE %colname% OR adres2 LIKE  %colname% OR gorod2 LIKE %colname%)
LIMIT 0, 50

Ошибка — отсутствует SELECT

2663 / 1727 / 175

Регистрация: 05.06.2011

Сообщений: 4,967

06.10.2013, 12:43

В последнем примере — однозначно. limit — фраза select, одиночно (к оператору в скобках) он не применяется. К исходному select какая ошибка?

0 / 0 / 0

Регистрация: 18.04.2013

Сообщений: 117

06.10.2013, 13:07

[ТС]

Сообщение от iifat

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘LIMIT 0, 10’ at line 1

_ViPeR_

614 / 488 / 175

Регистрация: 02.03.2010

Сообщений: 1,236

07.10.2013, 06:10

Выполнил вот такой запрос у себя

MySQL

(SELECT * FROM event WHERE event.typ = 0)
UNION
(SELECT * FROM event WHERE event.typ = 1)
LIMIT 0,10

Никакой ошибки. Не там копаете…

IT_Exp

Эксперт

87844 / 49110 / 22898

Регистрация: 17.06.2006

Сообщений: 92,604

07.10.2013, 06:10

Помогаю со студенческими работами здесь

LIMIT в IN
Нужна помощ!
Тут ошибка, как я поняла, в том, что нельзя использовать LIMIT в IN. Как ее обойти? …

update и limit
Здравствуйте!
Был такой запрос:

UPDATE `fruit`
SET `order` = ‘1’
WHERE `user_id` =…

LIMIT с переменными
Приветствую народ.
Что-то я никак не в курю в чем загвоздка.
В общем есть запрос:
CREATE…

Limit и subquery
Имеется таблица T с полями: id, date, price.
Нужно получить выборку, чтобы для каждого id были…

Искать еще темы с ответами

Или воспользуйтесь поиском по форуму:

Источник

Когда я запускаю этот запрос:

SELECT * FROM `forums_posts` WHERE pid < IS NULL ORDER BY pid DESC LIMIT 0,50

Версия MySQL: 5.5.5-10.1.13-MariaDB

Я получаю эту ошибку:

Ошибка: 1S111 / 1 В вашем синтаксисе SQL есть ошибка; проверьте руководство, которое соответствует вашей версии сервера MariaDB для права
синтаксис для использования около ‘IS NULL ORDER BY pid DESC LIMIT 0,50’ в строке 1

Что я делаю неправильно?

-5

Решение

Если вы хотите получить запись, где pid не равен NULL, попробуйте следующее:

SELECT * FROM `forums_posts` WHERE pid IS NOT NULL ORDER BY pid DESC LIMIT 0,50

Если вы хотите получить запись, где pid равен нулю, попробуйте следующее:

SELECT * FROM `forums_posts` WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50

Мы не можем использовать < > и еще один такой оператор с IS NULL.

Другие решения

Условие НЕДЕЙСТВИТЕЛЬНО или НЕДЕЙСТВИТЕЛЬНО. Не существует ‘pid< НУЛЕВОЙ’.

SELECT * FROM forums_posts WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50

Попробуй это

ВЫБРАТЬ ИЗ table_name ГДЕ ИДЕНТИФИКАЦИОННЫЙ НОМЕР ПО ИДЕНТИФИКАТОРУ DESC LIMIT 0,50

Вы используете неправильный запрос: pid < IS NULL ничего

Либо это будет

 SELECT * FROM `forums_posts` WHERE pid IS NOT NULL ORDER BY pid DESC LIMIT 0,50 // if you don't want NULL value

ИЛИ ЖЕ

SELECT * FROM `forums_posts` WHERE pid IS NULL ORDER BY pid DESC LIMIT 0,50 // if you want only NULL value

SELECT * FROM `forums_posts` WHERE pid < IS NULL ORDER BY pid DESC LIMIT 0,50

Так должно быть pid < IS NULL

Потому что в SQL каждый отдельный NULL отличается от другого значения NULL. Для этой цели мы не можем использовать <> как бы мы использовали для других.

Источник

I’m updating some old PHP code and ran across an issue I don’t completely understand. In the old days of mysql_* functions you could include a variable in your SQL query like:

$query = "SELECT * FROM table $limit";

Where $limit = "LIMIT 0,50";. Thus the complete query was

$query = "SELECT * FROM table LIMIT 0,50";

And everything worked fine. However, with PDO prepared statements and named parameters, this type of simple substitution doesn’t seem possible unless you break up the limit statement. For example:

$stmt = $conn->prepare('SELECT * FROM table :myLimit');
$stmt->execute(array(':myLimit'=>' LIMIT 0,50'));

Results in the error:

ERROR: SQLSTATE[42000]: Syntax error or access violation: 1064 You
have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near ‘?’ at line
1

But if I change that query to the following so that the LIMIT is broken down further:

$stmt = $conn->prepare('SELECT * FROM table LIMIT :start,:end ');
$stmt->execute(array(':start'=>0,':end'=>50));

It works great.

So why doesn’t using :myLimit as the named parameter and
array(':myLimit'=>' LIMIT 0,50') as the value work?
What are the
rules for using named parameters, and how do they differ from the
simple variable substitution in the SQL string that the old mysql_*
functions could use?

The PDO pages on php.net are a little ambiguous when it comes to what can and can’t be used as named parameters and I was looking for something a little more in-depth than what I found:

You must include a unique parameter marker for each value you wish to pass in to the statement
You cannot use a named parameter marker of the same name twice in a prepared statement.
You cannot bind multiple values to a single named parameter in, for example, the IN() clause of an SQL statement.

I’m currently using PHP 5.1.6

Источник

So, you’re creating a custom SQL query to perform a task in the database. After putting the code together and running it in PHPmyAdmin it responds with a 1064 error. It may look similar to this:

The 1064 error displays any time you have an issue with your SQL syntax, and is often due to using reserved words, missing data in the database, or mistyped/obsolete commands. So follow along and learn more about what the 1064 error is, some likely causes, and general troubleshooting steps.

Note: Since syntax errors can be hard to locate in long queries, the following online tools can often save time by checking your code and locating issues:

PiliApp MySQL Syntax Check
EverSQL SQL Query Syntax Check & Validator

Causes for the 1064 error

Reserved Words
Missing Data
Mistyped Commands
Obsolete Commands

This may seem cryptic since it is a general error pointing to a syntax issue in the SQL Query statement. Since the 1064 error can have multiple causes, we will go over the most common things that will result in this error and show you how to fix them. Follow along so you can get your SQL queries updated and running successfully.

Using Reserved Words

Every version of MySQL has its own list of reserved words. These are words that are used for specific purposes or to perform specific functions within the MySQL engine. If you attempt to use one of these reserved words, you will receive the 1064 error. For example, below is a short SQL query that uses a reserved word as a table name.

CREATE TABLE alter (first_day DATE, last_day DATE);

How to fix it:

Just because the word alter is reserved does not mean it cannot be used, it just has special requirements to use it as the MySQL engine is trying to call the functionality for the alter command. To fix the issue, you will want to surround the word with backticks, this is usually the button just to the left of the “1” button on the keyboard. The code block below shows how the code will need to look in order to run properly.

CREATE TABLE `alter` (first_day DATE, last_day DATE);

Missing Data

Sometimes data can be missing from the database. This causes issues when the data is required for a query to complete. For example, if a database is built requiring an ID number for every student, it is reasonable to assume a query will be built to pull a student record by that ID number. Such a query would look like this:

SELECT * from students WHERE studentID = $id

If the $id is never properly filled in the code, the query would look like this to the server:

SELECT * from students WHERE studentID =

Since there is nothing there, the MySQL engine gets confused and complains via a 1064 error.

How to fix it:

Hopefully, your application will have some sort of interface that will allow you to bring up the particular record and add the missing data. This is tricky because if the missing data is the unique identifier, it will likely need that information to bring it up, thus resulting in the same error. You can also go into the database (typically within phpMyAdmin) where you can select the particular row from the appropriate table and manually add the data.

Mistyping of Commands

One of the most common causes for the 1064 error is when a SQL statement uses a mistyped command. This is very easy to do and is easily missed when troubleshooting at first. Our example shows an UPDATE command that is accidentally misspelled.

UDPATE table1 SET id = 0;

How to fix it:

Be sure to check your commands prior to running them and ensure they are all spelled correctly.

Below is the syntax for the correct query statement.

UPDATE table1 SET id = 0;

Obsolete Commands

Some commands that were deprecated (slated for removal but still allowed for a period of time) eventually go obsolete. This means that the command is no longer valid in the SQL statement. One of the more common commands is the ‘TYPE‘ command. This has been deprecated since MySQL 4.1 but was finally removed as of version 5.1, where it now gives a syntax error. The ‘TYPE‘ command has been replaced with the ‘ENGINE‘ command. Below is an example of the old version:

CREATE TABLE t (i INT) TYPE = INNODB;

This should be replaced with the new command as below:

CREATE TABLE t (i INT) ENGINE = INNODB;

For developers or sysadmins experienced with the command line, get high availability and root access for your application, service, and websites with Cloud VPS Hosting.

Error 1064 Summary

As you can see there is more than one cause for the 1064 error within MySQL code. Now, you know how to correct the issues with your SQL Syntax, so your query can run successfully. This list will be updated as more specific instances are reported.

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