Ошибка no matching function for call to

The no matching function for call to C++ constructor error appears when the identification of the called process does not match the argument. For instance, whenever the compiler specifies no matching functions or methods exist, it indicates the compiler identified a function by an exact name in the command’s parameter.

Henceforth, we wrote this detailed no matching function for call to C++ array debugging guide to help you remove this annoying code exception without affecting other processes. In addition, we will help you recreate the no matching function for call to ‘getline C++ exception using standard elements and procedures that will help you pinpoint the bug.

Why Is the No Matching Function for Call to C++ Bug Happening?

The C++ no matching function for call to default constructor error happens and affects your programming experience when the identification of the called process does not match the argument. As a result, this error indicates the system cannot recognize the data type in your document due to identical names.

So, the no matching function for call to Arduino mistake can obliterate your program if you introduce many properties with identical ids. Consequently, the system will fail to read the adequate role, confusing developers about why and where the script launches exceptions, although all elements appear functional.

In addition, unfortunately, this creates unexpected obstacles because sometimes scanning the complete code will be essential to remove the no matching function for call to printf bug. However, we are far from discussing the possible debugging methods because you must learn how to recreate the full invalid exception and output.

So, the message is almost inevitable when we continue to pass the specific incorrect method or wrong parameter set to the function. The program will launch the no matching function for call to max C++ error because the function’s definition specifies the method’s name to the compiler.

In addition, your script explicitly declares the entire broken function or command content. As a result, having identical ids for several properties confuses your application and blocks further procedures launched by the incorrect command.

– Creating Public Classes in the Main Function

You will likely experience the no matching function for call to ‘stoi mistake when creating public classes in the primary function using typical elements. Unfortunately, as explained before, the syntax includes a few ids that provoke the system to launch the error.

You can learn more about the primary function and properties in the following example:

Although the tags and values appear correct, your system displays an exception indicating the broken functions. The following example provides the absolute error:

Unfortunately, the error can happen if your code calls specific commands with invalid parameters.

– Calling Commands With Invalid Parameters

Your system can sometimes prevent you from completing the code when your script calls several commands with invalid parameters.

Although this happens rarely, it can produce unexpected mistakes, especially with complex applications with many procedures. Therefore, we will show you a syntax that blocks the main function and halts further processes.

The following example provides the broken code:

After running the command and launching the properties, your system will display the following error:

This script calls the shuffle command with a failed parameter, which blocks further operations.

– Failing To Read the Standard Halts All Procedures

This article’s last invalid chapter recreates the matching function error in C++ and fails to read the standard, which halts all processes. Unfortunately, predicting when and where this happens is almost impossible, especially if you have a script with many operations and elements.

As a result, we will show you a short code snippet that launches the bug in the editing window, which affects the child tags, although the standard is not related. In addition, the template includes a few voids and targets that compile the application.

The following example provides the script that fails to read the standard:

Although appearing insignificant, the incorrect message indicates inconsistencies. Learn more about the message below:

This example completes our guide on recreating the mistake, so it is time to apply the most sophisticated debugging approaches.

How To Resolve the No Matching Function for Call to C++ Mistake?

You can resolve the no matching function for call to C++ error by providing corresponding and functional parameters to the broken function. In addition, you can quickly obliterate the bugged message by introducing different parameters for the various overloaded functions. Luckily, both approaches will not affect secondary processes and elements.

In addition, you can remove this error by changing the code to meet the command’s expectations. This procedure ensures your template has fair inputs the system can render effortlessly.

But first, let us simplify the script, as shown below:

Furthermore, as explained before, you can modify the properties to meet the function’s needs. The following example provides the best approach:

As you can tell, this method repairs this article’s last chapter that recreates the bug. Luckily, you can apply it to all documents and applications.

– Repair the Compiler Defaults

The second debugging approach fixes the compiler defaults that confuse your system. Follow the steps in this bullet list to delete the code exception:

• Choose Compiler Options in the tool menu.
• Select the Settings tab that appears in the pop-up windows.
• Locate and choose Code Generation in the next tab.
• Click on the arrow on the right on the Language Standard line.
• Choose ISO C++ 11 from the list box and press OK.

The mistake should disappear, and you can complete the project without further complications or errors.

Conclusion

The no-matching function for the call in C++ error appears when the identification of the called process does not match the argument. As a result, we explained the following critical points to help you debug the code:

• Checking the parameters of the required methods and their data type is critical
• We usually make mistakes when writing the arguments in the functions
• You can allow the process by providing the matched parameter
• Adding a new role in the exact data type set should remove the mistake

We are confident that you will no longer experience this annoying exception after applying these debugging principles. Luckily, the methods apply to similar matching function errors.

Доброго времени суток.

В качестве некоторой предыстории скажу, что начать изучать С++ довелось совсем недавно, и в процессе возникла некоторая неопределенность

При попытке реализовать наследование классов(в простейшем виде, но с header’ом) выдаёт ошибку:
«error: no matching function for call to ‘myclass::myclass()'»(ругается на файл myclass.cpp)

код «программы»

main.cpp

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#include <iostream>
#include<string>
 
using namespace std;
 
#include "myclass.h"
 
int main()
{
    string str;
    cout <<"Insert The String..."<<endl;
    getline(cin, str);
 
    int a;
    cout <<"Insert The Number..."<<endl;
    cin >>a;
 
    myclassDerived theOne(str, a);
    theOne.set_b(str);
    theOne.set_d(a);
    theOne.show_all();
    cout<<endl;
    return 0;
 
}

myclass.h

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#ifndef MYCLASS_H_INCLUDED
#define MYCLASS_H_INCLUDED
 
#include <string>
 
using namespace std;
 
 
class myclass
{
public:
    myclass(string s);
    void set_b(string s);
    string get_b();
    void show_b();
private:
    string b;
};
 
class myclassDerived: public myclass
{
public:
    myclassDerived(string strng, int i);
    void set_d(int i);
    int get_d();
    void show_d();
    void show_all();
private:
    int d;
 
};
 
#endif // MYCLASS_H_INCLUDED

myclass.cpp

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#include <iostream>
#include<string>
 
 
using namespace std;
 
#include "myclass.h"
 
 
 
myclass::myclass(string s)
{
    set_b(s);
}
 
void myclass::set_b(string s)
{
    b = s;
}
 
string myclass::get_b()
{
    return b;
}
 
void myclass::show_b()
{
    cout <<"The String is: "<< get_b()<<endl;
}
 
myclassDerived::myclassDerived(string strng, int i)
{
    set_d(i);
    set_b(strng);
}
 
void myclassDerived::set_d(int i)
{
    d = i;
}
 
int myclassDerived::get_d()
{
    return d;
}
 
void myclassDerived::show_d()
{
    cout << "The Number is" << get_d()<<endl;
}
void myclassDerived::show_all()
{
    cout <<"The String is "<< get_b()<<"The Number is" << get_d()<<endl;
}

возможно, я допускаю какую-то очень нубскую ошибку, но не вижу её?

How do we get this error?

If you try to compile the following program:

you’ll get this horrible error:

MyProgram.ino: In function 'void setup()':
MyProgram:21:23: error: no matching function for call to 'ArduinoJson6130_0000010::BasicJsonDocument<ArduinoJson6130_0000010::DefaultAllocator>::BasicJsonDocument()'
   DynamicJsonDocument doc;
                       ^~~
In file included from ArduinoJson/Document/DynamicJsonDocument.hpp:7:0,
                 from ArduinoJson.hpp:21,
                 from ArduinoJson.h:9,
                 from MyProgram.ino:9:
ArduinoJson/Document/BasicJsonDocument.hpp:56:3: note: candidate: ArduinoJson6130_0000010::BasicJsonDocument<TAllocator>::BasicJsonDocument(ArduinoJson6130_0000010::JsonVariant) [with TAllocator = ArduinoJson6130_0000010::DefaultAllocator]
   BasicJsonDocument(JsonVariant src)
   ^~~~~~~~~~~~~~~~~
ArduinoJson/Document/BasicJsonDocument.hpp:56:3: note:   candidate expects 1 argument, 0 provided
ArduinoJson/Document/BasicJsonDocument.hpp:49:3: note: candidate: template<class T> ArduinoJson6130_0000010::BasicJsonDocument<TAllocator>::BasicJsonDocument(const T&, typename ArduinoJson6130_0000010::enable_if<ArduinoJson6130_0000010::IsVisitable<T>::value>::type*)
   BasicJsonDocument(const T& src,
   ^~~~~~~~~~~~~~~~~
ArduinoJson/Document/BasicJsonDocument.hpp:49:3: note:   template argument deduction/substitution failed:
MyProgram.ino:21:23: note:   candidate expects 2 arguments, 0 provided
   DynamicJsonDocument doc;
                       ^~~
In file included from ArduinoJson/Document/DynamicJsonDocument.hpp:7:0,
                 from ArduinoJson.hpp:21,
                 from ArduinoJson.h:9,
                 from MyProgram.ino:9:
ArduinoJson/Document/BasicJsonDocument.hpp:42:3: note: candidate: ArduinoJson6130_0000010::BasicJsonDocument<TAllocator>::BasicJsonDocument(const ArduinoJson6130_0000010::BasicJsonDocument<TAllocator>&) [with TAllocator = ArduinoJson6130_0000010::DefaultAllocator]
   BasicJsonDocument(const BasicJsonDocument& src)
   ^~~~~~~~~~~~~~~~~
ArduinoJson/Document/BasicJsonDocument.hpp:42:3: note:   candidate expects 1 argument, 0 provided
ArduinoJson/Document/BasicJsonDocument.hpp:39:12: note: candidate: ArduinoJson6130_0000010::BasicJsonDocument<TAllocator>::BasicJsonDocument(size_t, TAllocator) [with TAllocator = ArduinoJson6130_0000010::DefaultAllocator; size_t = unsigned int]
   explicit BasicJsonDocument(size_t capa, TAllocator allocator = TAllocator())
            ^~~~~~~~~~~~~~~~~
ArduinoJson/Document/BasicJsonDocument.hpp:39:12: note:   candidate expects 2 arguments, 0 provided

Understanding the error

It’s a long output, but it’s not that complicated.
Once you remove all the noise (namespaces, template parameters, file paths…), it’s just:

error: no matching function for call to 'BasicJsonDocument::BasicJsonDocument()'
   DynamicJsonDocument doc;
                       ^~~

note: candidate: BasicJsonDocument::BasicJsonDocument(JsonVariant)
   BasicJsonDocument(JsonVariant src)
   ^~~~~~~~~~~~~~~~~
note:   candidate expects 1 argument, 0 provided

note: candidate: template<class T> BasicJsonDocument::BasicJsonDocument(const T&, typename enable_if<IsVisitable<T>::value>::type*)
   BasicJsonDocument(const T& src,
   ^~~~~~~~~~~~~~~~~
note:   template argument deduction/substitution failed:
note:   candidate expects 2 arguments, 0 provided

note: candidate: BasicJsonDocument::BasicJsonDocument(const BasicJsonDocument&)
   BasicJsonDocument(const BasicJsonDocument& src)
   ^~~~~~~~~~~~~~~~~
note:   candidate expects 1 argument, 0 provided

note: candidate: BasicJsonDocument::BasicJsonDocument(size_t, TAllocator)
   explicit BasicJsonDocument(size_t capa, TAllocator allocator = TAllocator())
            ^~~~~~~~~~~~~~~~~
note:   candidate expects 2 arguments, 0 provided

What does it mean?

What the compiler is trying to say is this: when compiling DynamicJsonDocument doc;, I’ve been looking for BasicJsonDocument::BasicJsonDocument() but I didn’t find it. Instead, I found:

1. BasicJsonDocument(JsonVariant src)
2. BasicJsonDocument(const T&, typename enable_if<IsVisitable<T>::value>::type*)
3. BasicJsonDocument(const BasicJsonDocument& src)
4. BasicJsonDocument(size_t capa, TAllocator allocator = TAllocator())

So, the compiler tried to find a constructor with no parameter, but it didn’t find one.
This means we forgot to pass an argument to the constructor.

How does this relate to DynamicJsonDocument?

DynamicJsonDocument is an alias of BasicJsonDocument; it’s defined like that:

typedef BasicJsonDocument<DefaultAllocator> DynamicJsonDocument;

That’s why the compiler says BasicJsonDocument when we use DynamicJsonDocument

How to solve the error?

To fix this error, you must pass an argument to the constructor of DynamicJsonDocument.
It’s an integer that specifies the capacity of the memory pool; it’s a mandatory argument in ArduinoJson 6.

DynamicJsonDocument doc(capacity);

To choose the right capacity for your project, use the ArduinoJson Assistant, or read How to determine the capacity of the JsonDocument?

Передать в шаблонную функци массив можно двумя способами:

1) Передача по ссылке:

template<class T, std::size_t s1, std::size_t s2>
void func(T(& name)[s1][s2])
{
    std::cout << "Array by reference" << std::endl;
    std::cout << s1 << " " << s2 << std::endl;
    std::cout << name[0][0] << " " << name[s1 - 1][s2 - 1] << std::endl;
}

int main()
{
    int mas[2][3] = { {0, 1, 2}, {3, 4, 5} };
    func(mas);
}

2) Передача по указателю:

template<class T, std::size_t s1, std::size_t s2>
void func2(T(*name)[s1][s2])
{
    std::cout << "Array by pointer" << std::endl;
    std::cout << s1 << " " << s2 << std::endl;
    std::cout << (*name)[0][0] << " " << (*name)[s1 - 1][s2 - 1] << std::endl;
}

int main()
{
    int mas[2][3] = { {0, 1, 2}, {3, 4, 5} };
    func2(&mas);
}

В принципе можно передавать массив как просто указатель и потом кастовать к типу массива или двойному указателю, но не думаю что это то что Вам нужно, да и, как по мне, не очень это правильно.