Ошибка при миграции django

asked Nov 12, 2015 at 21:39

I got the same problem (column not exist) but when I try to run migrate not with makemigrations

• Cause: I removed the migration files and replaced them with single pretending intial migration file 0001 before running the migration for the last change

• Solution:

  1. Drop tables involved in that migration of that app (consider a backup workaround if any)
  2. Delete the rows responsible of the migration of that app from the table django_migrations in which migrations are recorded, This is how Django knows which migrations have been applied and which still need to be applied.

And here is how solve this problem:

• log in as postgres user (my user is called posgres):

  sudo -i -u postgres

• Open an sql terminal and connect to your database:

  psql -d database_name

• List your table and spot the tables related to that app:

  dt

• Drop them (consider drop order with relations):

  DROP TABLE tablename ;
• List migration record, you will see migrations applied classified like so:

id | app | name | applied
—+——+———+———+

SELECT * FROM django_migrations;

• Delete rows of migrations of that app (you can delete by id or by app, with app don’t forget ‘quotes’):

  DELETE FROM django_migrations WHERE app='your_app';

• log out and run your migrations merely (maybe run makemigrations in your case):

  python manage.py migrate --settings=your.settings.module_if_any

Note: it is possible that in your case will not have to drop all the tables of that app and not all the migrations, just the ones of the models causing the problem.

I wish this can help.

answered May 30, 2018 at 10:44

Run into this problem after the migration of my postgres database to a differnt server. Somehow I messed up the database and could not update my model with the new class UserProfile.

I solved the problem creating initial migration for existing schema:

1. Empty the django_migrations table: delete from django_migrations;with a command DELETE FROM django_migrations WHERE app='my_app';
2. For every app, delete its migrations folder: rm -rf <app>/migrations/
3. Reset the migrations for the «built-in» apps: python manage.py migrate --fake
4. For each app run: python manage.py makemigrations <app>. Take care of dependencies (models with ForeignKey’s should run after their parent model).
5. Finally: python manage.py migrate --fake-initial

Got it here: https://stackoverflow.com/a/29898483

PS I’m not sure that this was relevant to the resolution of the problem but, first, I dropped the table in postgresql that caused an error and commented out the UserProfile class in models.

in shell:

 sudo -su postgres
 psql databse_name   
 DROP TABLE table_name;

models.py:

#class UserProfile(models.Model):
    #user = models.OneToOneField(settings.AUTH_USER_MODEL, unique=True, primary_key=True, on_delete=models.CASCADE, related_name='user_profile')
    #avatar = ThumbnailerImageField(upload_to='profile_images', blank=True)
    #country = models.CharField(max_length = 128)

I ran into this problem recently after upgrading to Django 1.11. I wanted to permanently address the issue so I wouldn’t have to comment / uncomment code every time I ran a migration on the table, so my approach:

from django.db.utils import ProgrammingError as AvoidDataMigrationError

try:
    ... do stuff that breaks migrations
except AvoidDataMigrationError:
    pass

I rename the exception during import to AvoidDataMigrationError so it’s clear why it’s there.

answered Nov 9, 2018 at 14:03

Just now had the same error when I tried to migrate a SingletonModel to actually contain the necessary fields.

Reason for the error was that my Model A used some fields of this SingletonModel (as configurable values). And during instantation of model A during the migration process it obviously couldn’t guarantee that my migration was safe.

A colleague had a wonderful idea. Make the default value for the field a function call, and therefor lazy.

Example:

class A (models.Model):
    default_value = models.DecimalField(default: lambda: SingletonModel.get_solo().value, ...)

So therefor, my advice:
Try and make the offending call (seen in stacktrace) a lazy one.

answered Jul 19, 2019 at 12:57

I got the same issue, here is my case:
in the app MyApp I add a new field to the model:

class Advisors(models.Model):
    AdvID = models.IntegerField(primary_key=True)
    Name = models.CharField(max_length=200,null=False)
    ParentID = models.IntegerField(null=True) # <--- the NEW field I add

so what I did is:
in the urls.py of MyProject, NOT MyApp, comment out the url() linked to MyApp and then do makemigrations and migrate everything goes well;
in MyApp/urls.py file:

urlpatterns = [
    url(r'^admin/', admin.site.urls, name='admin'),
    url(r'^$', views.HomePage.as_view(),name='home'),
    #comment out the following line, after migrate success, bring it back;
    # url(r'^myapp/', include('myapp.urls',namespace='research')), <--- 
]

answered Dec 5, 2019 at 22:30

Late to the party, but there is some info I want to share. It helped me a lot!

I am using django-solo to store app config in database, and I got the same issue as Alex when adding new field to configuration model. Stacktrace pointed me to the line where I’m getting config from database: conf = SiteConfiguration().get_solo().

There is a closed issue for django-solo project on Github. The idea is to make model loading lazy (exactly as MrKickkiller pointed before).

So for modern Django version (in my case 3.0) this code works perfectly:

from django.utils.functional import SimpleLazyObject
conf = SimpleLazyObject(SiteConfiguration.get_solo)

answered Mar 9, 2020 at 10:51

Stuck into this issue recently.

In my case, I added a reference to a non-existing field in the code, then I came to the model file and added the new field, then tried to run makemigrations command which thrown the above error.

So I went to the stack trace all the way up and found the newly added reference was the problem. commented that out, ran makemigrations and voila.

answered Aug 21, 2018 at 20:13

answered Nov 12, 2019 at 15:46

I faced this problem. for solving problem follow the step.
1.open Database and table.
2.Create a required(sites_site.airport_codes in question ) column which was not exits in
your table with default value.

3.run the command

python manage.py makemigrations

python manage.py migrate <app name>

python manage.py runserver

answered Jul 8, 2020 at 13:51

Got the same issue, thanks to this thread to point me out the way by exploring the backtrace.

In a ListView declaration, I was declaring a queryset with a filter pointing to the model I was trying to update, without overiding the get_query_set() function.

    class BacklogListView(ListView):
        model = Version
        context_object_name = 'vhs'
        template_name = 'backlog_list.html'    
        queryset = VersionHistory.objects.filter(extract=Extract.objects.last())

fixed by:

    class BacklogListView(ListView):
        model = Version
        context_object_name = 'vhs'
        template_name = 'backlog_list.html'
    
        def get_queryset(self):
            queryset = VersionHistory.objects.filter(extract=Extract.objects.last())

If it can help someone…

answered Jan 8, 2021 at 15:58

You might have a RunPython using the new state of the model you need before modifying your database, to fix that, always use apps.get_model

def forwards_func(apps, schema_editor):
    # We get the model from the versioned app registry;
    # if we directly import it, it'll be the wrong version
    SiteModel = apps.get_model('my_app', 'Site')

    # DONT
    from my_app.models import Site

def reverse_func(apps, schema_editor):
    ...

answered Jan 19, 2021 at 2:12

This issue happens when you try to migrate an app X which has a related attribute to an app Y before Y migrate.

So, to solve it you have to make the migrations of Y first.
You can specify the order migrations by using the django dependencies property

You can also, run:

python manage.py migrate --run-syncdb

then for every error caused app (like django.db.utils.ProgrammingError: relation "AppName_attribute" does not exist)run:

python manage.py migrate AppName

P.S:

If you need to reset the db schema, you can use:

manage.py reset_schema

And don’t forget to remove all migrations files:

find . | grep -E "(__pycache__|.pyc|.pyo$|migrations)" | xargs rm -rf

answered Apr 1, 2021 at 13:21

For my case i am getting the error when migrating. I solved the issue using the below steps.

After makemigration the created file was.

# Example:
class Migration(migrations.Migration):

    dependencies = [
        ('app1', '0030_modify'),
    ]

    operations = [
        migrations.RemoveField(
            model_name='users',
            name='phone1',
        ),
        migrations.RemoveField(
            model_name='users',
            name='phone2',
        ),
        migrations.AlterUniqueTogether(
            name='users',
            unique_together={('email', 'phone')},
        ),
        
    ]

I solved the issue by moving the unique_together migration first, then field removals.

# Example:
class Migration(migrations.Migration):

    dependencies = [
        ('app1', '0030_modify'),
    ]

    operations = [
        migrations.AlterUniqueTogether(
            name='users',
            unique_together={('email', 'phone')},
        ),
        migrations.RemoveField(
            model_name='users',
            name='phone1',
        ),
        migrations.RemoveField(
            model_name='users',
            name='phone2',
        ),
    ]

Hope it will solve your problem

answered Jul 9, 2021 at 8:50