Ошибка tuple index out of range

Please Help me. I’m running a simple python program that will display the data from mySQL database in a tkinter form…

from Tkinter import *
import MySQLdb

def button_click():
    root.destroy()

root = Tk()
root.geometry("600x500+10+10")
root.title("Ariba")

myContainer = Frame(root)
myContainer.pack(side=TOP, expand=YES, fill=BOTH)

db = MySQLdb.connect ("localhost","root","","chocoholics")
s = "Select * from member"
cursor = db.cursor()
cursor.execute(s)
rows = cursor.fetchall()

x = rows[1][1] + " " + rows[1][2]
myLabel1 = Label(myContainer, text = x)
y = rows[2][1] + " " + rows[2][2]
myLabel2 = Label(myContainer, text = y)
btn = Button(myContainer, text = "Quit", command=button_click, height=1, width=6)

myLabel1.pack(side=TOP, expand=NO, fill=BOTH)
myLabel2.pack(side=TOP, expand=NO, fill=BOTH)
btn.pack(side=TOP, expand=YES, fill=NONE)

Thats the whole program….

The error was

x = rows[1][1] + " " + rows[1][2]
IndexError: tuple index out of range

y = rows[2][1] + " " + rows[2][2]
IndexError: tuple index out of range

Can anyone help me??? im new in python.

Thank you so much….

Иногда выскакивает такая ошибка, в чем проблема ? Вообще не понимаю из за чего она появляется. Не всегда появляется

def db_fetchall(sql, params = {}, first_entry = False):
    #
    _data = []
    
    #
    try:
        _cursor.execute(sql, params)
        _data = _cursor.fetchall() if(first_entry != True) else _cursor.fetchall()[0]

    except pymysql.Error as e:
        print(e)

    #
    return _data

def db_get_account_by_chat_id(a_chat):
    #
    params = {
        "a_chat": a_chat 
    }

    #
    return db_fetchall("SELECT * FROM `accounts` WHERE `a_chat` = %(a_chat)s ORDER BY `id` DESC LIMIT 1", params, True)

Сами ошибки:

File "app.py", line 87, in db_get_account_by_chat_id
    return db_fetchall("SELECT * FROM `accounts` WHERE `a_chat` = %(a_chat)s ORDER BY `id` DESC LIMIT 1", params, True)

  File "app.py", line 72, in db_fetchall
    _data = _cursor.fetchall() if(first_entry != True) else _cursor.fetchall()[0]

IndexError: tuple index out of range

Like lists, Python tuples are indexed. This means each value in a tuple has a number you can use to access that value. When you try to access an item in a tuple that does not exist, Python returns an error that says “tuple index out of range”.

In this guide, we explain what this common Python error means and why it is raised. We walk through an example scenario with this problem present so that we can figure out how to solve it.

Problem Analysis: IndexError: tuple index out of range

Tuples are indexed starting from 0. Every subsequent value in a tuple is assigned a number that is one greater than the last. Take a look at a tuple:

birds = ("Robin", "Collared Dove", "Great Tit", "Goldfinch", "Chaffinch")

This tuple contains five values. Each value has its own index number:

To access the value “Robin” in our tuple, we would use this code:

Our code returns: Robin. We access the value at the index position 1 and print it to the console. We could do this with any value in our list.

If we try to access an item that is outside our tuple, an error will be raised.

An Example Scenario

Let’s write a program that prints out the last three values in a tuple. Our tuple contains a list of United Kingdom cities. Let’s start by declaring a tuple:

cities = ("Edinburgh", "London", "Southend", "Bristol", "Cambridge")

Next, we print out the last three values. We will do this using a for loop and a range() statement. The range() statement creates a list of numbers between a particular range so that we can iterate over the items in our list whose index numbers are in that range.

Here is the code for our for loop:

for i in range(3, 6):
	print(birds[i])

Let’s try to run our code:

Goldfinch
Chaffinch
Traceback (most recent call last):
  File "main.py", line 4, in <module>
	print(birds[i])
IndexError: tuple index out of range

Our code prints out the values Goldfinch and Chaffinch. These are the last two values in our list. It does not print out a third value.

The Solution

Our range() statement creates a list of numbers between the range of 3 and 6. This list is inclusive of 3 and exclusive of 6. Our list is only indexed up to 4. This means that our loop will try to access a bird at the index position 5 in our tuple because 5 is in our range.

Let’s see what happens if we try to print out birds[5] individually:

Our code returns:

Traceback (most recent call last):
  File "main.py", line 3, in <module>
	print(birds[5])
IndexError: tuple index out of range

The same error is present. This is because we try to access items in our list as if they are indexed from 1. Tuples are indexed from 0.

To solve this error, we need to revise our range() statement so it only prints the last three items in our tuple. Our range should go from 2 to 5:

for i in range(2, 5):
	print(birds[i])

Let’s run our revised code and see what happens:

Great Tit
Goldfinch
Chaffinch

Our code successfully prints out the last three items in our list. We’re now accessing items at the index positions 2, 3, and 4. All of these positions are valid so our code now works.

Conclusion

The IndexError: tuple index out of range error occurs when you try to access an item in a tuple that does not exist. To solve this problem, make sure that whenever you access an item from a tuple that the item for which you are looking exists.

The most common cause of this error is forgetting that tuples are indexed from 0. Start counting from 0 when you are trying to access a value from a tuple. As a beginner, this can feel odd. As you spend more time coding in Python, counting from 0 will become second-nature.

Now you’re ready to solve this Python error like an expert!

In this article, we will explain what causes IndexError: tuple index out of range in Python. Some common causes of this error such as incorrect comparison conditions in loops or wrong initialization values. Let’s go into the specific situation and figure out how to fix it.

What causes the error “IndexError: tuple index out of range” in Python

The error occurs when you want to go to an index that is out of range of the tuple. Look at this program that prints out the values in a tuple.

fruits = ("apple", "banana", "cherry")

# Use for loop to iterate over elements in a tuple.
for i in range(3):
	print(fruits[i])

Output:

apple
banana
cherry

And when we change range(3) to range(4), the above error occurs:

fruits = ("apple", "banana", "cherry")

for i in range(4):
	print(fruits[i])

Output:

Traceback (most recent call last):
  File "./example.py", line 3, in <module>
IndexError: tuple index out of range

The tuple has only 3 indexes: 0,1,2 but for loop wants to access the 3rd index position, so the error happens.

Solutions for “IndexError: tuple index out of range” error

Using For loop

We can use len() function to check the length of the tuple first and then use a for loop to iterate over the items so we avoid the error.

Example:

fruits = ("apple", "banana", "cherry") 

# Use "len()" and for loop
for i in range(len(fruits)):
	print(fruits[i])

Output:

apple
banana
cherry

Using While Loop

fruits = ("apple", "banana", "cherry")
i = 0

while i < len(fruits):
    print(fruits[i])
    i += 1

Output:

apple
banana
cherry

len() function will return a tuple length of 3, so the loop will run 4 times because the initial value of i is 0. We will not use “<=” in this case, but should only use “<“, the variable i will not be able to equal the length of the tuple, and the code will not access the 4th element of the tuple. So the error won’t happen.

Using Try… Except to catch this error

We should only loop within the tuple’s index range. Avoid letting the loop access out of the tuple’s scope and make sure the item exists in the tuple. You can use Try… Except to catch this error, preventing the program from stopping.

fruits = ("apple", "banana", "cherry")
try:  
  for i in range(4):
      print(fruits[i])
except IndexError:
  print("Something went wrong")

Output:

apple
banana
cherry
Something went wrong

Summary

The error “IndexError: tuple index out of range” in Python has been solved. In many cases, It would help if you used the len() function to check the range of the tuple first. Pay attention to the index range of the tuple while writing the program so you can avoid this error. We hope you like it. Good luck to you!

The IndexError: Tuple Index Out Of Range error is a common type of index error that arises while dealing with tuple-related codes. These errors are generally related to indexing in tuples which are pretty easy to fix.

This guide will help you understand the error and how to solve it.

What is a Tuple?

Tuples are one of the four built-in single-variable objects used to store multiple items. Similar to other storage for data collection like List, Sets, and, Dictionary, Tuple is also a storage of data that is ordered and unchangeable. Similar to lists, the items here are also indexed. It is written with round brackets. Unlike other storage data sets, Tuples can have duplicate items, which means the data in a tuple can be present more than once. Also, Tuples can have different data types, such as integers, strings, booleans, etc.

To determine the length of a tuple, the len() function is used. And to get the last item in a tuple, you need to use [- index number of the item you want].

Example: –

a_tuple = (0, [4, 5, 6], (7, 8, 9), 8.0)

What is IndexError?

An IndexError is a pretty simple error that arises when you try to access an invalid index. It usually occurs when the index object is not present, which can be caused because the index being more extensive than it should be or because of some missing information. This usually occurs with indexable objects like strings, tuples, lists, etc. Usually, the indexing starts with 0 instead of 1, so sometimes IndexError happens when one individual tries to go by the 1, 2, 3 numbering other than the 0, 1, 2 indexing.

For example, there is a list with three items. If you think as a usual numbering, it will be numbered 1, 2, and 3. But in indexing, it will start from 0.

Example: –

x = [1, 2, 3, 4]

print(x[5]) #This will throw error

The IndexError: tuple index out-of-range error appears when you try to access an index which is not present in a tuple. Generally, each tuple is associated with an index position from zero “0” to n-1. But when the index asked for is not present in a tuple, it shows the error.

Causes for IndexError: Tuple Index Out Of Range?

In general, the IndexError: Tuple Index Out Of Range error occurs at times when someone tries to access an index which is not currently present in a tuple. That is accessing an index that is not present in the tuple, which can be caused due to the numbering. This can be easily fixed if we correctly put the information.

This can be understood by the example below. Here the numbers mentioned in the range are not associated with any items. Thus this will raise the IndexError: Tuple Index Out Of Range.

Syntax:-

fruits = ("Apple", "Orange", "Banana")
for i in range(1,4):
    print(fruits[i]) # Only 1, and 2 are present. Index 3 is not valid.

Solution for IndexError: Tuple Index Out Of Range

The IndexError: tuple index out-of-range error can be solved by following the solution mentioned below.

For example, we consider a tuple with a range of three, meaning it has three items. In a tuple, the items are indexed from 0 to n-1. That means the items would be indexed as 0, 1, and 2.

In this case, if you try to access the last item in the tuple, we need to go for the index number 2, but if we search for the indexed numbered three, it will show the IndexError: Tuple Index Out Of Range error. Because, unlike a list, a tuple starts with 0 instead of 1.

So to avoid the IndexError: Tuple Index Out Of Range error, you either need to put the proper range or add extra items to the tuple, which will show the results for the searched index.

Syntax: –

fruits = ("Apple", "Orange", "Banana")
for i in range(3):
  print(fruits[i])

FAQs

Conclusion

The article here will help you understand the error as well as find a solution to it. Apart from that, the IndexError: tuple index out-of-range error is a common error that can be easily solved by revising the range statement or the indexing. The key to solving this error is checking for the items’ indexing.

References

• Tuples
• Range

To learn more about some common errors follow Python Clear’s errors section.