R1714 python ошибка - Не ошибается лишь тот, кто ничего не делает!

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Message emitted:

Consider merging these comparisons with 'in' by using '%s %sin (%s)'. Use a set instead if elements are hashable.

Description:

To check if a variable is equal to one of many values, combine the values into a set or tuple and check if the variable is contained «in» it instead of checking for equality against each of the values. This is faster and less verbose.

Problematic code:

def fruit_is_round(fruit):
    # +1: [consider-using-in]
    return fruit == "apple" or fruit == "orange" or fruit == "melon"

Correct code:

def fruit_is_round(fruit):
    return fruit in {"apple", "orange", "melon"}

Created by the refactoring checker.

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R1714 (consider-using-in)

❌ Problematic code:

array = list(range(10))
n = input()

for elem in array:
    if int(n) == elem:
        pass

✔️ Correct code:

array = list(range(10))
n = input()

if int(n) in array:
    pass

Rationale:

To check if a variable is equal to one of many values,combine the values into
a tuple and check if the variable is contained in it instead of checking
for equality against each of the values. This is faster and less verbose.

Related resources:

Issue Tracker

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My Code :

def modify_book():
        db = mysql.connector.connect(host='localhost',
                                     database='library',
                                     user='Aishwary_Pandey',
                                     password='aishwary')
        c = db.cursor()
        clear()
        print('M O D I F Y  --  B O O K  --  D E T A I L S')
        print('-'*120)
        print('n1. Book Title')
        print('n2. Book Author')
        print('n3. Book Publisher')
        print('n4. Book Pages')
        print('n5. Book Price')
        print('n6. Book Edition')
        print('n7. Exit')
        print('nn')
        choice = int(input('Enter your choice : '))
        field = ''
        if choice == 1:
            field = 'title'
        if choice == 2:
            field = 'author'
        if choice == 3:
            field = 'publisher'
        if choice == 4:
            field = 'pages'
        if choice == 5:
            field = 'price'
        if choice == 6:
            field = 'edition'
    
        book_id = input('Enter ID of the Book : ')
        value = input('Enter the Value to be Updated : ')
        if field == 'pages' or field == 'price':
            sql = 'update book set ' + field + ' = '+value+' where id = '+book_id+';'
        else:
            sql = 'update book set ' + field + ' = "'+value+'" where id = '+book_id+';'

error :
basically there is no error but my idle (spyder) suggested me to merge these comparisons with «in» to «field in (‘pages’, ‘price’)» which I am not able to understand how would I do that.

please help.

asked Mar 5, 2021 at 6:57

This should «fix» it

if field in ('pages', 'price'):
    sql = 'update book set ' + field + ' = '+value+' where id = '+book_id+';'
else:
    sql = 'update book set ' + field + ' = "'+value+'" where id = '+book_id+';'

answered Aug 25, 2021 at 13:17

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consider-using-in (R1714)

Consider merging these comparisons with ‘in’ by using ‘%s %sin (%s)’.
Use a set instead if elements are hashable. To check if a variable is
equal to one of many values, combine the values into a set or tuple and
check if the variable is contained «in» it instead of checking for
equality against each of the values. This is faster and less verbose.

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pylint-errors

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A curated list of pylint errors with explanation and examples

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